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Find-1-2-3-3-3-3-3-n-3-n-




Question Number 214860 by hardmath last updated on 21/Dec/24
Find:  1+  (2^3 /(3!))  +  (3^3 /(3!))  +  ...  +  (n^3 /(n!))  =  ?
$$\mathrm{Find}: \\ $$$$\mathrm{1}+\:\:\frac{\mathrm{2}^{\mathrm{3}} }{\mathrm{3}!}\:\:+\:\:\frac{\mathrm{3}^{\mathrm{3}} }{\mathrm{3}!}\:\:+\:\:…\:\:+\:\:\frac{\mathrm{n}^{\mathrm{3}} }{\mathrm{n}!}\:\:=\:\:? \\ $$

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