Question-215004

Question Number 215004 by efronzo1 last updated on 25/Dec/24

Commented by mr W last updated on 26/Dec/24

$$\left({xy}+\frac{\lambda^{\mathrm{2}} }{{xy}}\right)_{{min}} =\frac{\mathrm{1}}{\mathrm{4}}+\mathrm{4}\lambda^{\mathrm{2}} \\ $$