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Question Number 138350 by abenarhodym last updated on 12/Apr/21
(√2)((√8)−(2/( (√8))))
$$\sqrt{\mathrm{2}}\left(\sqrt{\mathrm{8}}−\frac{\mathrm{2}}{\:\sqrt{\mathrm{8}}}\right) \\ $$
Answered by Ñï= last updated on 12/Apr/21
(√2)((√8)−(2/( (√8))))=2^(1/2) (2^(3/2) −2^(1−(3/2)) )=2^((1/2)+(3/2)) −2^((1/2)−(1/2)) =2^2 −2^0 =3
$$\sqrt{\mathrm{2}}\left(\sqrt{\mathrm{8}}−\frac{\mathrm{2}}{\:\sqrt{\mathrm{8}}}\right)=\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}} \left(\mathrm{2}^{\frac{\mathrm{3}}{\mathrm{2}}} −\mathrm{2}^{\mathrm{1}−\frac{\mathrm{3}}{\mathrm{2}}} \right)=\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{3}}{\mathrm{2}}} −\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{2}}} =\mathrm{2}^{\mathrm{2}} −\mathrm{2}^{\mathrm{0}} =\mathrm{3} \\ $$
Answered by Rasheed.Sindhi last updated on 12/Apr/21
=(√2)(2(√2)−(2/(2(√2))))  =2.2−((2(√2))/(2(√2)))  =4−1=3
$$=\sqrt{\mathrm{2}}\left(\mathrm{2}\sqrt{\mathrm{2}}−\frac{\mathrm{2}}{\mathrm{2}\sqrt{\mathrm{2}}}\right) \\ $$$$=\mathrm{2}.\mathrm{2}−\frac{\mathrm{2}\sqrt{\mathrm{2}}}{\mathrm{2}\sqrt{\mathrm{2}}} \\ $$$$=\mathrm{4}−\mathrm{1}=\mathrm{3} \\ $$
Answered by cherokeesay last updated on 12/Apr/21
= (√2)(((8 −2)/( (√8)))) = ((√(16))/8)×6 = (1/2)×6 = 3
$$=\:\sqrt{\mathrm{2}}\left(\frac{\mathrm{8}\:−\mathrm{2}}{\:\sqrt{\mathrm{8}}}\right)\:=\:\frac{\sqrt{\mathrm{16}}}{\mathrm{8}}×\mathrm{6}\:=\:\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{6}\:=\:\mathrm{3} \\ $$

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