Solve-If-4-2-2y-1-16-4-y-1-and-8-3-2x-1-2-9-2-x-what-is-2x-y-

Question Number 217982 by Unhombre last updated on 24/Mar/25

S o l v e

I f 4^{2^{2 y - 1}} = 16^{4^{y + 1}} a n d 8^{3^{2 x - 1}} = 2^{9^{2 - x}}

w h a t i s 2 x + y ?

Commented by mr W last updated on 25/Mar/25

i f 4^{2^{2 y - 1}} = 16^{4^{y + 1}}, t h e n

2^{2 y - 1} = 2 \times 4^{y + 1} = 2 \times 2^{2 (y + 1)} = 2^{2 (y + 1) + 1}

\Rightarrow 2 y - 1 = 2 (y + 1) + 1

\Rightarrow 2 y - 1 = 2 y + 2 + 1

\Rightarrow - 1 = 3 ? ? ?

\Rightarrow n o s u c h y \in R e x i s t s!

\Rightarrow q u e s t i o n i s w r o n g!

Commented by Unhombre last updated on 25/Mar/25

I t h i n k s o b e c a u s e w h a t e v e r f o r m u l a I

u s e d t h e a n s w e r w o u l d b e i n v a l i d

T h a n k s