Question Number 227294 by Spillover last updated on 12/Jan/26
Commented by Spillover last updated on 12/Jan/26
$${find}\:{shaded}\:{area}\:{of}\:{rectangle}\:{above} \\ $$
Answered by Spillover last updated on 12/Jan/26
Commented by Spillover last updated on 12/Jan/26
$${case}\:\mathrm{1} \\ $$
Answered by Spillover last updated on 12/Jan/26
Commented by Spillover last updated on 12/Jan/26
$${case}\:\mathrm{2} \\ $$
Answered by Spillover last updated on 12/Jan/26
Answered by Spillover last updated on 12/Jan/26
Answered by Spillover last updated on 12/Jan/26
Answered by TonyCWX last updated on 13/Jan/26
$$\mathrm{Let}\:\mathrm{x}\:=\:\mathrm{area}\:\mathrm{of}\:\mathrm{leftmost}\:\mathrm{unshaded}\:\mathrm{triangle} \\ $$$$\mathrm{y}\:=\:\mathrm{area}\:\mathrm{of}\:\mathrm{middle}\:\mathrm{unshaded}\:\mathrm{triangle} \\ $$$$\mathrm{a}\:=\:\mathrm{area}\:\mathrm{of}\:\mathrm{shaded}\:\mathrm{region} \\ $$$$\mathrm{x}\:=\:\mathrm{y} \\ $$$$\mathrm{a}\:=\:\mathrm{2x} \\ $$$$\mathrm{a}+\mathrm{x}\:=\:\mathrm{15}+\mathrm{y}+\mathrm{8} \\ $$$$\mathrm{a}\:=\:\mathrm{23} \\ $$
Commented by Spillover last updated on 13/Jan/26
$${thank}\:{you} \\ $$