Question Number 73901 by azizullah last updated on 16/Nov/19
Answered by $@ty@m123 last updated on 16/Nov/19
$$\mathrm{42}\:{m} \\ $$
Commented by azizullah last updated on 16/Nov/19
$$\boldsymbol{\mathrm{sir}}\:\boldsymbol{\mathrm{need}}\:\boldsymbol{\mathrm{work}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{solution}}. \\ $$
Answered by $@ty@m123 last updated on 16/Nov/19
$${Let}\:{AB}\:{be}\:{a}\:{tower}.\:\left({Draw}\:{it}.\right) \\ $$$${Let}\:{BC}=\mathrm{42}\:{m}\: \\ $$$${ATQ} \\ $$$$\angle{ACB}=\mathrm{45}^{\mathrm{o}} \\ $$$$\Rightarrow\:\angle{BAC}=\mathrm{45}^{\mathrm{o}} \\ $$$$\Rightarrow{AB}={BC} \\ $$$$\Rightarrow{AB}=\mathrm{42}\:{m} \\ $$
Commented by azizullah last updated on 17/Nov/19
$$\:\:\:\:\:\mathrm{thanks}\:\mathrm{alot}\:\mathrm{sir}\:\mathrm{G} \\ $$