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Find-the-volume-of-the-solid-that-lies-within-the-sphere-x-2-y-2-z-2-16-above-the-x-y-plane-and-below-the-cone-z-x-2-y-2-




Question Number 74117 by necxxx last updated on 19/Nov/19
Find the volume of the solid that lies  within the sphere x^2 +y^2 +z^2 =16, above  the x-y plane and below the cone  z=(√(x^2 +y^2 ))
$${Find}\:{the}\:{volume}\:{of}\:{the}\:{solid}\:{that}\:{lies} \\ $$$${within}\:{the}\:{sphere}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} =\mathrm{16},\:{above} \\ $$$${the}\:{x}-{y}\:{plane}\:{and}\:{below}\:{the}\:{cone} \\ $$$${z}=\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} } \\ $$
Commented by necxxx last updated on 19/Nov/19
please help
$${please}\:{help} \\ $$

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