Question Number 9096 by tawakalitu last updated on 17/Nov/16
Answered by mrW last updated on 19/Nov/16
$${let}\:{R}_{\mathrm{1}} \:{and}\:{R}_{\mathrm{2}} \:{be}\:{the}\:{rent}\:{of}\:{the}\:{first} \\ $$$${and}\:{second}\:{house}\:{last}\:{year}. \\ $$$$\frac{{R}_{\mathrm{1}} }{{R}_{\mathrm{2}} }=\frac{\mathrm{16}}{\mathrm{23}} \\ $$$${R}_{\mathrm{1}} =\frac{\mathrm{16}}{\mathrm{23}}{R}_{\mathrm{2}} \\ $$$$\frac{\mathrm{1}.\mathrm{25}{R}_{\mathrm{1}} }{{R}_{\mathrm{2}} +\mathrm{5200}}=\frac{\mathrm{9}}{\mathrm{11}} \\ $$$$\mathrm{1}.\mathrm{25}×\mathrm{11}{R}_{\mathrm{1}} =\mathrm{9}{R}_{\mathrm{2}} +\mathrm{9}×\mathrm{5200} \\ $$$$\mathrm{1}.\mathrm{25}×\mathrm{11}×\frac{\mathrm{16}}{\mathrm{23}}{R}_{\mathrm{2}} =\mathrm{9}{R}_{\mathrm{2}} +\mathrm{9}×\mathrm{5200} \\ $$$$\left(\mathrm{1}.\mathrm{25}×\mathrm{11}×\frac{\mathrm{16}}{\mathrm{23}}−\mathrm{9}\right){R}_{\mathrm{2}} =\mathrm{9}×\mathrm{5200} \\ $$$${R}_{\mathrm{2}} =\frac{\mathrm{23}}{\mathrm{13}}×\mathrm{9}×\mathrm{5200}=\mathrm{82800}\:\$ \\ $$$${R}_{\mathrm{1}} =\frac{\mathrm{16}}{\mathrm{23}}×\mathrm{82800}=\mathrm{57600}\:\$ \\ $$
Commented by tawakalitu last updated on 19/Nov/16
$$\mathrm{Thanks}\:\mathrm{so}\:\mathrm{much}\:\mathrm{sir}.\:\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}. \\ $$
Commented by tawakalitu last updated on 19/Nov/16
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}. \\ $$