Question Number 140225 by mondli last updated on 05/May/21
$${x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{3}=\mathrm{0}\:\: \\ $$
Answered by MJS_new last updated on 05/May/21
$${x}^{\mathrm{2}} +{px}+{q}=\mathrm{0}\:\Rightarrow\:{x}=−\frac{{p}}{\mathrm{2}}\pm\sqrt{\frac{{p}^{\mathrm{2}} }{\mathrm{4}}−{q}} \\ $$