If-r-2-x-ea-2-y-2-and-s-2-x-ea-2-y-2-and-r-s-2a-Prove-that-r-a-ex-s-a-ex-and-that-x-2-1-e-2-y-2-a-2-1-e-2-

Question Number 9199 by tawakalitu last updated on 22/Nov/16

$$\mathrm{If}\:\:\mathrm{r}^{\mathrm{2}} \:=\:\left(\mathrm{x}\:+\:\mathrm{ea}\right)^{\mathrm{2}} \:+\:\mathrm{y}^{\mathrm{2}} \:\mathrm{and}\:\mathrm{s}^{\mathrm{2}} \:=\:\left(\mathrm{x}\:−\:\mathrm{ea}\right)^{\mathrm{2}} \:+\:\mathrm{y}^{\mathrm{2}} \\ $$$$\mathrm{and}\:\mathrm{r}\:+\:\mathrm{s}\:=\:\mathrm{2a},\:\mathrm{Prove}\:\mathrm{that}: \\ $$$$\mathrm{r}\:=\:\mathrm{a}\:+\:\mathrm{ex},\:\:\mathrm{s}\:=\:\mathrm{a}\:−\:\mathrm{ex},\:\mathrm{and}\:\mathrm{that}, \\ $$$$\mathrm{x}^{\mathrm{2}} \left(\mathrm{1}\:−\:\mathrm{e}^{\mathrm{2}} \right)\:+\:\mathrm{y}^{\mathrm{2}} \:=\:\mathrm{a}^{\mathrm{2}} \left(\mathrm{1}\:−\:\mathrm{e}^{\mathrm{2}} \right) \\ $$

Commented by 123456 last updated on 22/Nov/16

$${r}^{\mathrm{2}} +{s}^{\mathrm{2}} =\mathrm{2}{y}^{\mathrm{2}} +\left({x}+{ea}\right)^{\mathrm{2}} +\left({x}−{ea}\right)^{\mathrm{2}} \\ $$$${r}^{\mathrm{2}} +{s}^{\mathrm{2}} =\mathrm{2}{y}^{\mathrm{2}} +{x}^{\mathrm{2}} +\mathrm{2}{ea}+\left({ea}\right)^{\mathrm{2}} +{x}^{\mathrm{2}} −\mathrm{2}{ea}+\left({ea}\right)^{\mathrm{2}} \\ $$$${r}^{\mathrm{2}} +{s}^{\mathrm{2}} =\mathrm{2}\left[{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +\left({ea}\right)^{\mathrm{2}} \right] \\ $$$${r}+{s}=\mathrm{2}{a} \\ $$$$\left({r}+{s}\right)^{\mathrm{2}} =\mathrm{4}{a}^{\mathrm{2}} \\ $$$${r}^{\mathrm{2}} +{s}^{\mathrm{2}} +\mathrm{2}{rs}=\mathrm{4}{a}^{\mathrm{2}} \\ $$$$\mathrm{2}\left[{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +\left({ea}\right)^{\mathrm{2}} +{rs}\right]=\mathrm{4}{a}^{\mathrm{2}} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +\left({ea}\right)^{\mathrm{2}} +{rs}=\mathrm{2}{a}^{\mathrm{2}} \\ $$

Commented by tawakalitu last updated on 23/Nov/16

$$\mathrm{I}\:\mathrm{appreciate}\:\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}. \\ $$

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