Question Number 75254 by must1987 last updated on 09/Dec/19
Answered by 21042004 last updated on 09/Dec/19
$$\mathrm{1}.\:{B}=\left\{\mathrm{1},\mathrm{2},\mathrm{6}\right\} \\ $$$$\left.\mathrm{2}.\:{a}\right)\:{A}\cup{B}=\left\{\mathrm{1},\mathrm{2},\mathrm{3},\mathrm{4},\mathrm{5},\mathrm{6},\mathrm{7},\mathrm{8},\mathrm{9},\mathrm{10}\right\} \\ $$$$\left.\:\:\:\:\:{b}\right)\:{Yes} \\ $$$$\left.\mathrm{3}.\:{a}\right)\:{A}'=\left\{\mathrm{0},\mathrm{1},\mathrm{3},\mathrm{5},\mathrm{7},\mathrm{9}\right\} \\ $$$$\left.\:\:\:\:\:{b}\right)\:{A}\cap{A}'=\varnothing \\ $$$$\left.\:\:\:\:\:{c}\right)\:{A}\cup{A}'=\left\{\mathrm{0},\mathrm{1},\mathrm{2},\mathrm{3},\mathrm{4},\mathrm{5},\mathrm{6},\mathrm{7},\mathrm{8},\mathrm{9}\right\} \\ $$$$\left.\:\:\:\:\:{d}\right)\:\left({A}'\right)'=\left\{\mathrm{2},\mathrm{4},\mathrm{6},\mathrm{8}\right\} \\ $$$$\left.\:\:\:\:\:{e}\right)\:\varnothing−{U}=−{U}? \\ $$$$\left.\:\:\:\:\:{f}\right)\:\varnothing'={U}? \\ $$$$\left.\:\:\:\:\:{g}\right)\:{U}'=\varnothing? \\ $$$$\mathrm{4}.\:{Answer}\:{of}\:{exercise}\:\mathrm{3} \\ $$