Question Number 9831 by tawakalitu last updated on 06/Jan/17
Answered by ridwan balatif last updated on 06/Jan/17
$$\mathrm{Area}_{\mathrm{AC}} =\mathrm{Area}_{\mathrm{ABC}} =\mathrm{Area}_{\mathrm{AB}} \\ $$$$\mathrm{Area}_{\mathrm{AC}} +\mathrm{Area}_{\mathrm{ABC}} +\mathrm{Area}_{\mathrm{AB}} =\mathrm{Area}\:\mathrm{of}\:\mathrm{circle} \\ $$$$\mathrm{3}×\mathrm{Area}_{\mathrm{ABC}} =\pi\mathrm{r}^{\mathrm{2}} \\ $$$$\mathrm{Area}_{\mathrm{ABC}} =\frac{\mathrm{25}}{\mathrm{3}}\pi \\ $$
Commented by tawakalitu last updated on 06/Jan/17
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}. \\ $$
Commented by RasheedSoomro last updated on 13/Jan/17
$$\mathrm{region}\:\mathrm{ABC}\left(\mathrm{red}\right)\:\:\mathrm{in}\:\mathrm{the}\:\mathrm{question}\:\mathrm{is}\:\mathrm{not}\:\mathrm{a}\:\:\:\bigtriangleup\mathrm{ABC}. \\ $$$$\blacktriangle\mathrm{ABC}=\mathrm{red}\:\mathrm{region}−\mathrm{segment}\:\mathrm{BC} \\ $$$$\mathrm{segmentBC}\:\mathrm{means}\:\mathrm{closed}\:\mathrm{region}\:\mathrm{made}\:\mathrm{by}\:\mathrm{arcBC} \\ $$$$\mathrm{and}\:\mathrm{chord}\:\mathrm{BC}. \\ $$