Question Number 76213 by Emmanuel_N last updated on 25/Dec/19
$$\left(\frac{\mathrm{1}}{\mathrm{64}}×\mathrm{5}^{−\mathrm{3}} \right)^{−\frac{\mathrm{1}}{\mathrm{3}}} \\ $$
Answered by MJS last updated on 25/Dec/19
$$=\left(\mathrm{4}^{−\mathrm{3}} ×\mathrm{5}^{−\mathrm{3}} \right)^{−\frac{\mathrm{1}}{\mathrm{3}}} =\left(\mathrm{20}^{−\mathrm{3}} \right)^{−\frac{\mathrm{1}}{\mathrm{3}}} =\mathrm{20}^{−\mathrm{3}×\left(−\frac{\mathrm{1}}{\mathrm{3}}\right)} =\mathrm{20} \\ $$