Question Number 10853 by geovane10math last updated on 27/Feb/17
$$\left({x}\:+\:{y}\right)^{{n}} \:=\:\underset{{k}=\mathrm{0}} {\overset{{n}} {\sum}}\begin{pmatrix}{{n}}\\{{k}}\end{pmatrix}{x}^{{k}} {y}^{{n}−{k}} \\ $$$$\left({x}\:−\:{y}\right)^{{n}} \:=\:??????? \\ $$
Answered by mrW1 last updated on 27/Feb/17
$$\left({x}\:−\:{y}\right)^{{n}} \:=\:\underset{{k}=\mathrm{0}} {\overset{{n}} {\sum}}\begin{pmatrix}{{n}}\\{{k}}\end{pmatrix}\left(−\mathrm{1}\right)^{{n}−{k}} {x}^{{k}} {y}^{{n}−{k}} \\ $$
Commented by geovane10math last updated on 27/Feb/17
$$\mathrm{Thanks}! \\ $$