Question-76442 Tinku Tara June 3, 2023 Integration 0 Comments FacebookTweetPin Question Number 76442 by aliesam last updated on 27/Dec/19 Answered by Tanmay chaudhury last updated on 28/Dec/19 x=tanadx=sec2adasec−1(1+tan2a1−tan2a)→sec−1(sec2a)=2a∫2atana×a×sec2ada2∫d(tana)tana→2ln(tana)so2∣lnx∣ee2=soansweris2(lne2−lne)=2(2−1)=2 Commented by aliesam last updated on 28/Dec/19 godblessyousir Commented by Tanmay chaudhury last updated on 28/Dec/19 thankyousir Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: express-in-partial-fraction-3x-2-x-2-1-x-1-Next Next post: how-evaluate-lim-x-0-1-1-x-2-cos-x-x-4- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.