Question Number 11228 by uni last updated on 17/Mar/17
Answered by mrW1 last updated on 17/Mar/17
$$\left(_{\mathrm{2}} ^{\mathrm{6}} \right)×\left(_{\mathrm{1}} ^{\mathrm{4}} \right)+\left(_{\mathrm{2}} ^{\mathrm{4}} \right)×\left(_{\mathrm{1}} ^{\mathrm{6}} \right)=\frac{\mathrm{6}×\mathrm{5}}{\mathrm{2}}×\mathrm{4}+\frac{\mathrm{4}×\mathrm{3}}{\mathrm{2}}×\mathrm{6}=\mathrm{96} \\ $$$$\left.\Rightarrow{E}\right) \\ $$