Menu Close

Question-11425




Question Number 11425 by tawa last updated on 25/Mar/17
Answered by mrW1 last updated on 25/Mar/17
(1) 12C5=792  (2) 9C5+3×(9C4)+3×(9C3)=126+3×126+3×84=756  (3) 10C5+10C3=252+120=372
$$\left(\mathrm{1}\right)\:\mathrm{12}{C}\mathrm{5}=\mathrm{792} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{9}{C}\mathrm{5}+\mathrm{3}×\left(\mathrm{9}{C}\mathrm{4}\right)+\mathrm{3}×\left(\mathrm{9}{C}\mathrm{3}\right)=\mathrm{126}+\mathrm{3}×\mathrm{126}+\mathrm{3}×\mathrm{84}=\mathrm{756} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{10}{C}\mathrm{5}+\mathrm{10}{C}\mathrm{3}=\mathrm{252}+\mathrm{120}=\mathrm{372} \\ $$
Commented by tawa last updated on 25/Mar/17
God bless you sir
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *