Question Number 76973 by Maclaurin Stickker last updated on 02/Jan/20
$${In}\:{a}\:{ABC}\:{triangle}\:{the}\:{side}\:\boldsymbol{{a}}=\mathrm{6}\:{and} \\ $$$$\boldsymbol{{c}}^{\mathrm{2}} −\boldsymbol{{b}}^{\mathrm{2}} =\mathrm{66}.\:{Calculate}\:{the}\:{projections} \\ $$$${of}\:{sides}\:\boldsymbol{{b}}\:{and}\:\boldsymbol{{c}}\:{on}\:\boldsymbol{{a}}. \\ $$
Answered by jagoll last updated on 02/Jan/20
$$\mathrm{projections}\:\mathrm{of}\:\mathrm{sides}\:\mathrm{b}\:\mathrm{on}\:\mathrm{a}\:=\:\frac{\mathrm{17}}{\mathrm{2}} \\ $$
Answered by jagoll last updated on 02/Jan/20
$$\mathrm{projections}\:\mathrm{sides}\:\mathrm{c}\:\mathrm{on}\:\mathrm{a}\:=\:\frac{\mathrm{17}}{\mathrm{2}}−\mathrm{6}=\frac{\mathrm{5}}{\mathrm{2}} \\ $$
Commented by Maclaurin Stickker last updated on 02/Jan/20
$${Show}\:{how}\:{you}\:{got}\:{the}\:{solution}. \\ $$
Commented by jagoll last updated on 02/Jan/20
Commented by jagoll last updated on 02/Jan/20
$$\mathrm{i}'\mathrm{m}\:\mathrm{correct}\:\mathrm{my}\:\mathrm{answer} \\ $$
Commented by Maclaurin Stickker last updated on 02/Jan/20
$${perfect} \\ $$