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S-ABCD-3-2-2-BAO-MAO-22-5-BCM-DCM-S-AOB-




Question Number 11880 by @ANTARES_VY last updated on 03/Apr/17
S_(ABCD) =3+2(√2)  ∠BAO=∠MAO=22,5°  ∠BCM=∠DCM  S_(AOB) =?
$$\boldsymbol{\mathrm{S}}_{\boldsymbol{\mathrm{ABCD}}} =\mathrm{3}+\mathrm{2}\sqrt{\mathrm{2}} \\ $$$$\angle\boldsymbol{\mathrm{BAO}}=\angle\boldsymbol{\mathrm{MAO}}=\mathrm{22},\mathrm{5}° \\ $$$$\angle\boldsymbol{\mathrm{BCM}}=\angle\boldsymbol{\mathrm{DCM}} \\ $$$$\boldsymbol{\mathrm{S}}_{\boldsymbol{\mathrm{AOB}}} =? \\ $$

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