1-y-z-x-z-z-y-y-x-2-x-2-z-x-xy-z-y-y-2-0-3-z-x-z-x-z-y-2z-y-

Tinku Tara June 3, 2023 Algebra 0 Comments

Question Number 143006 by mathdanisur last updated on 08/Jun/21

1. y(∂z/∂x) + z(∂z/∂y) = (y/x) 2. x^2 (∂z/∂x) − xy(∂z/∂y) + y^2 = 0 3. { (((∂z/∂x) = (z/x))),(((∂z/∂y) = ((2z)/y))) :}

$$\mathrm{1}.\:{y}\frac{\partial{z}}{\partial{x}}\:+\:{z}\frac{\partial{z}}{\partial{y}}\:=\:\frac{{y}}{{x}} \\ $$$$\mathrm{2}.\:{x}^{\mathrm{2}} \frac{\partial{z}}{\partial{x}}\:−\:{xy}\frac{\partial{z}}{\partial{y}}\:+\:{y}^{\mathrm{2}} \:=\:\mathrm{0} \\ $$$$\mathrm{3}.\:\begin{cases}{\frac{\partial{z}}{\partial{x}}\:=\:\frac{{z}}{{x}}}\\{\frac{\partial{z}}{\partial{y}}\:=\:\frac{\mathrm{2}{z}}{{y}}}\end{cases} \\ $$

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1-y-z-x-z-z-y-y-x-2-x-2-z-x-xy-z-y-y-2-0-3-z-x-z-x-z-y-2z-y-

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