Question Number 12080 by sin (x) last updated on 12/Apr/17
Answered by ajfour last updated on 12/Apr/17
![f(−1,3)=max(−4,−(1/3))=((−1)/3) g(4,4)=min(8, 16) =8 f[f(−1,3), g(4,4)] = f(−(1/3), 8)=max(−((25)/3), −(1/(24))) = −(1/(24)) (D) .](https://www.tinkutara.com/question/Q12081.png)
$${f}\left(−\mathrm{1},\mathrm{3}\right)=\mathrm{max}\left(−\mathrm{4},−\frac{\mathrm{1}}{\mathrm{3}}\right)=\frac{−\mathrm{1}}{\mathrm{3}} \\ $$$${g}\left(\mathrm{4},\mathrm{4}\right)={min}\left(\mathrm{8},\:\mathrm{16}\right)\:=\mathrm{8} \\ $$$${f}\left[{f}\left(−\mathrm{1},\mathrm{3}\right),\:{g}\left(\mathrm{4},\mathrm{4}\right)\right] \\ $$$$\:\:\:=\:{f}\left(−\frac{\mathrm{1}}{\mathrm{3}},\:\mathrm{8}\right)={max}\left(−\frac{\mathrm{25}}{\mathrm{3}},\:−\frac{\mathrm{1}}{\mathrm{24}}\right) \\ $$$$\:\:\:=\:−\frac{\mathrm{1}}{\mathrm{24}}\:\:\:\:\:\left({D}\right)\:. \\ $$