Question Number 12331 by tawa last updated on 19/Apr/17
Answered by mrW1 last updated on 19/Apr/17
$${m}\frac{{v}^{\mathrm{2}} }{{r}}\leqslant\mu{mg} \\ $$$$\mu\geqslant\frac{{v}^{\mathrm{2}} }{{rg}}=\frac{\mathrm{5}^{\mathrm{2}} }{\mathrm{8}×\mathrm{9}.\mathrm{81}}=\mathrm{0}.\mathrm{32} \\ $$
Commented by tawa last updated on 19/Apr/17
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$
Answered by By, Dismas RB last updated on 20/Apr/17
$${data} \\ $$$$\:{verocity}=\mathrm{5}.\mathrm{0}{m}/{s} \\ $$$${distance}=\mathrm{8}.\mathrm{0}{m} \\ $$$${required} \\ $$