Question Number 143653 by mim24 last updated on 16/Jun/21
Answered by ajfour last updated on 16/Jun/21
$${x}^{\mathrm{2}} −\mathrm{6}{x}−\mathrm{2}\sqrt{\mathrm{3}}=\mathrm{0} \\ $$$${x}_{\mathrm{1}} {x}_{\mathrm{2}} =−\mathrm{2}\sqrt{\mathrm{3}} \\ $$$${x}_{\mathrm{1}} +{x}_{\mathrm{2}} =\mathrm{6} \\ $$$$\mid{x}_{\mathrm{1}} −{x}_{\mathrm{2}} \mid=\sqrt{\mathrm{36}+\mathrm{8}\sqrt{\mathrm{3}}} \\ $$$$\:\: \\ $$