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0-pi-4-tanx-Li-tan-2-x-dx-




Question Number 143715 by Ar Brandon last updated on 17/Jun/21
∫_0 ^(π/4) tanx∙Li(tan^2 x)dx
$$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \mathrm{tanx}\centerdot\mathrm{Li}\left(\mathrm{tan}^{\mathrm{2}} \mathrm{x}\right)\mathrm{dx} \\ $$

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