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x-2-y-2-56-13-2-and-x-5y-12-56-12-find-x-y-




Question Number 143832 by mathdanisur last updated on 18/Jun/21
x^2  + y^2  = (((56)/(13)))^2  and  x + ((5y)/(12)) = ((56)/(12))  find  x+y=?
x2+y2=(5613)2andx+5y12=5612findx+y=?
Answered by MJS_new last updated on 18/Jun/21
x^2 +y^2 =p  x+qy=r ⇒ y=((r−x)/q) insert in the 1^(st)  equation  leads to  x^2 −((2r)/(q^2 +1))x−((pq^2 −r^2 )/(q^2 +1))=0  solve this for x and you′re done
x2+y2=px+qy=ry=rxqinsertinthe1stequationleadstox22rq2+1xpq2r2q2+1=0solvethisforxandyouredone
Commented by mathdanisur last updated on 19/Jun/21
thanks Sir..
thanksSir..
Answered by mitica last updated on 18/Jun/21
(1∙x+(5/(12))∙y)^2 ≤(1^2 +((5/(12)))^2 )(x^2 +y^2 )=(((56)/(12)))^2 ⇒  (x/1)=(y/(5/(12)))⇒y=((5x)/(12))⇒x+((25x)/(144))=((56)/(12))⇒x=((56∙12)/(169))=((48)/(13))⇒y=((20)/(13))
(1x+512y)2(12+(512)2)(x2+y2)=(5612)2x1=y512y=5x12x+25x144=5612x=5612169=4813y=2013
Commented by mathdanisur last updated on 19/Jun/21
thanks sir, but answer: x+y=((952)/(169))
thankssir,butanswer:x+y=952169
Answered by mr W last updated on 19/Jun/21
x+y=s  s−((7y)/(12))=((56)/(12))⇒y=((12s−56)/7)  x=s−y=((−5s+56)/7)  (((−5s+56)/7))^2 +(((12s−56)/7))^2 =(((56)/(13)))^2   s^2 −((1904)/(13^2 ))s+((906304)/(13^4 ))=0  (s−((952)/(13^2 )))^2 =0  ⇒s=((952)/(169))=x+y
x+y=ss7y12=5612y=12s567x=sy=5s+567(5s+567)2+(12s567)2=(5613)2s21904132s+906304134=0(s952132)2=0s=952169=x+y
Commented by mathdanisur last updated on 19/Jun/21
cool dear Sir thank you..
cooldearSirthankyou..

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