Question Number 13098 by ketto last updated on 14/May/17
Answered by Joel577 last updated on 14/May/17
$${GCD}\:\left({x}^{\mathrm{2}} {y}^{\mathrm{2}} ,\:\mathrm{4}{xy}^{\mathrm{4}} \right)\:=\:{xy}^{\mathrm{2}} \\ $$$${x}^{\mathrm{2}} {y}^{\mathrm{2}} \:+\:\mathrm{4}{xy}^{\mathrm{4}} \:=\:{xy}^{\mathrm{2}} \left({x}\:+\:\mathrm{4}{y}^{\mathrm{2}} \right) \\ $$