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Question Number 13234 by tawa tawa last updated on 17/May/17
The angle of elevation of the sun is 27°.  A man is 180 cm tall . How long is  his shadow. Give your answer to the nearest  10cm
$$\mathrm{The}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{elevation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{sun}\:\mathrm{is}\:\mathrm{27}°.\:\:\mathrm{A}\:\mathrm{man}\:\mathrm{is}\:\mathrm{180}\:\mathrm{cm}\:\mathrm{tall}\:.\:\mathrm{How}\:\mathrm{long}\:\mathrm{is} \\ $$$$\mathrm{his}\:\mathrm{shadow}.\:\mathrm{Give}\:\mathrm{your}\:\mathrm{answer}\:\mathrm{to}\:\mathrm{the}\:\mathrm{nearest}\:\:\mathrm{10cm} \\ $$
Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 17/May/17
l=180.tg27^° #90 cm
$${l}=\mathrm{180}.{tg}\mathrm{27}^{°} #\mathrm{90}\:{cm} \\ $$
Answered by RasheedSindhi last updated on 18/May/17
tan 27°=((180)/x) [x is length of shadow]  x=180/tan 27°≈350 cm
$$\mathrm{tan}\:\mathrm{27}°=\frac{\mathrm{180}}{\mathrm{x}}\:\left[\mathrm{x}\:\mathrm{is}\:\mathrm{length}\:\mathrm{of}\:\mathrm{shadow}\right] \\ $$$$\mathrm{x}=\mathrm{180}/\mathrm{tan}\:\mathrm{27}°\approx\mathrm{350}\:\mathrm{cm} \\ $$

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