Question Number 132181 by aurpeyz last updated on 12/Feb/21
Commented by aurpeyz last updated on 12/Feb/21
$$\boldsymbol{{no}}\:\mathrm{10}\:\boldsymbol{{pls}} \\ $$
Answered by ajfour last updated on 12/Feb/21
$$\theta={r}^{\mathrm{3}} −{r} \\ $$$${d}\theta=\left(\mathrm{3}{r}^{\mathrm{2}} −\mathrm{1}\right){dr} \\ $$$$\Rightarrow\:\bigtriangleup\theta\approx\left(\mathrm{3}×\mathrm{1}−\mathrm{1}\right)\left(\mathrm{0}.\mathrm{05}\right) \\ $$$$\:\:\:\:\:\:\bigtriangleup\theta\approx\mathrm{0}.\mathrm{1} \\ $$