Menu Close

Author: Tinku Tara

At-what-value-of-a-does-the-system-of-equations-have-4-solutions-x-2-y-2-0-x-a-2-y-2-1-

Question Number 209520 by Ismoiljon_008 last updated on 12/Jul/24 $$ \\ $$$$\:\:\:{At}\:{what}\:{value}\:{of}\:\:{a}\:{does}\:{the}\:{system} \\ $$$$\:\:\:{of}\:{equations}\:{have}\:\mathrm{4}\:{solutions}\:? \\ $$$$\:\:\:\left\{\:{x}^{\mathrm{2}} −{y}^{\mathrm{2}} =\mathrm{0}\right. \\ $$$$\:\:\:\left\{\left({x}−{a}\right)^{\mathrm{2}} +{y}^{\mathrm{2}} =\mathrm{1}\right. \\ $$$$ \\…

three-points-are-randomly-selected-on-a-circle-to-form-a-triangle-1-find-the-probability-that-the-center-of-the-circle-lies-inside-the-triangle-2-find-the-probability-that-the-triangle-is-an-acu

Question Number 209510 by mr W last updated on 12/Jul/24 $${three}\:{points}\:{are}\:{randomly}\:{selected} \\ $$$${on}\:{a}\:{circle}\:{to}\:{form}\:{a}\:{triangle}.\: \\ $$$$\left.\mathrm{1}\right)\:{find}\:{the}\:{probability}\:{that}\:{the}\:{center} \\ $$$${of}\:{the}\:{circle}\:{lies}\:{inside}\:{the}\:{triangle}. \\ $$$$\left.\mathrm{2}\right)\:{find}\:{the}\:{probability}\:{that}\:{the}\: \\ $$$${triangle}\:{is}\:{an}\:{acute}\:{triangle}. \\ $$ Terms of…

x-y-z-1-42x-44y-30z-42-x-y-z-1-0-0-yes-but-solution-

Question Number 209436 by hardmath last updated on 10/Jul/24 $$\begin{cases}{\mathrm{x}\:+\:\mathrm{y}\:+\:\mathrm{z}\:=\:\mathrm{1}}\\{\mathrm{42x}\:+\:\mathrm{44y}\:+\:\mathrm{30z}\:=\:\mathrm{42}}\end{cases} \\ $$$$\left(\mathrm{x},\mathrm{y},\mathrm{z}\right)=\left(\mathrm{1},\mathrm{0},\mathrm{0}\right)\:\mathrm{yes},\:\mathrm{but}\:\mathrm{solution}… \\ $$ Commented by mr W last updated on 10/Jul/24 $${you}\:{mean}\:{integer}\:{solutions}. \\ $$…

Question-209465

Question Number 209465 by RoseAli last updated on 10/Jul/24 Answered by mr W last updated on 10/Jul/24 $${x}−\mathrm{2}=\mathrm{0}\:\Rightarrow{x}=\mathrm{2} \\ $$$${x}−\mathrm{2}=\pm\mathrm{1}\:\Rightarrow{x}=\mathrm{1}\:{or}\:\mathrm{3} \\ $$$$\mathrm{10}{x}^{\mathrm{2}} −\mathrm{1}=\mathrm{3}{x}\:\Rightarrow\left(\mathrm{2}{x}−\mathrm{1}\right)\left(\mathrm{5}{x}+\mathrm{1}\right)=\mathrm{0}\:\Rightarrow{x}=−\frac{\mathrm{1}}{\mathrm{5}}\:{or}\:\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\Rightarrow\mathrm{5}\:{solutions}…

Question-209433

Question Number 209433 by essaad last updated on 10/Jul/24 Answered by A5T last updated on 10/Jul/24 $${S}_{{p}} =\frac{\mathrm{1}×\mathrm{2}×\mathrm{3}×\mathrm{4}×…×\left(\mathrm{2}{p}\right)}{\mathrm{2}×\mathrm{4}×\mathrm{6}×…×\mathrm{2}{p}}=\frac{\left(\mathrm{2}{p}\right)!}{\mathrm{2}^{{p}} \left(\mathrm{1}×\mathrm{2}×…×{p}\right)} \\ $$$$=\frac{\left(\mathrm{2}{p}\right)!}{\mathrm{2}^{{p}} {p}!}\Rightarrow{C} \\ $$ Terms…