Question Number 226855 by Kassista last updated on 17/Dec/25 Answered by mehdee7396 last updated on 17/Dec/25 $${x}^{\mathrm{2}} +\mathrm{4}{x}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{4}=\mathrm{4}\Rightarrow{x}=\mathrm{0},\frac{\mathrm{8}}{\mathrm{5}} \\ $$$$\Rightarrow{P}\left(\mathrm{0},,\mathrm{2}\right)\:\&\:\:{Q}\left(\frac{\mathrm{8}}{\mathrm{5}},−\frac{\mathrm{6}}{\mathrm{5}}\right)\Rightarrow{m}_{{PQ}} =−\frac{\mathrm{3}}{\mathrm{4}} \\ $$$$\Rightarrow{tan}\alpha=\frac{\mathrm{3}}{\mathrm{4}}\backsimeq\mathrm{36}^{\mathrm{0}} \Rightarrow\angle{POQ}\backsimeq\mathrm{126}^{\mathrm{0}}…
Question Number 226880 by Spillover last updated on 17/Dec/25 Answered by TonyCWX last updated on 18/Dec/25 $$\int_{\mathrm{0}} ^{\mathrm{1}} \left[\mathrm{2}^{{x}} \right]\mathrm{d}{x} \\ $$$$=\:\int_{\mathrm{0}} ^{\mathrm{1}} \left[{e}^{{x}\mathrm{ln}\left(\mathrm{2}\right)} \right]\mathrm{d}{x}…
Question Number 226882 by hardmath last updated on 17/Dec/25 Answered by breniam last updated on 17/Dec/25 $$=\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{{n}}{\:\frac{\sqrt[{{n}}]{\mathrm{2}^{{n}+\mathrm{1}} }−\mathrm{1}}{\:\sqrt[{{n}}]{\mathrm{2}}−\mathrm{1}}}=\underset{{n}\rightarrow\infty} {\mathrm{lim}}\frac{{n}\left(\sqrt[{{n}}]{\mathrm{2}}−\mathrm{1}\right)}{\mathrm{2}\sqrt[{{n}}]{\mathrm{2}}−\mathrm{1}} \\ $$$$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\left(\mathrm{2}\sqrt[{{n}}]{\mathrm{2}}−\mathrm{1}\right)=\mathrm{2}−\mathrm{1}=\mathrm{1} \\ $$$$\underset{{x}\rightarrow\infty}…
Question Number 226815 by CrispyXYZ last updated on 16/Dec/25 $$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left(\underset{{n}\rightarrow\infty} {\mathrm{lim}}\left(\mathrm{cos}\:\frac{{x}}{\mathrm{2}}\:\mathrm{cos}\:\frac{{x}}{\mathrm{2}^{\mathrm{2}} }\:…\:\mathrm{cos}\:\frac{{x}}{\mathrm{2}^{{n}} }\right)\right)\:=\:? \\ $$ Answered by AgniMath last updated on 16/Dec/25 $${sin}\mathrm{2}\theta\:=\:\mathrm{2}{sin}\theta{cos}\theta \\…
Question Number 226828 by fantastic2 last updated on 16/Dec/25 $$\frac{{d}^{\pi} }{{dx}^{\pi} }\left({x}^{\pi} \right)=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 226829 by Estevao last updated on 16/Dec/25 Answered by Estevao last updated on 17/Dec/25 $${Good} \\ $$ Answered by mr W last updated…
Question Number 226830 by Estevao last updated on 16/Dec/25 Answered by TonyCWX last updated on 31/Dec/25 $$\mathrm{27}\:=\:\mathrm{3}^{\mathrm{3}} \:=\:^{\mathrm{2}} \mathrm{3} \\ $$$$\:^{\mathrm{2}} {x}\:=\:\mathrm{2} \\ $$$${x}^{{x}} =\mathrm{2}…
Question Number 226820 by Spillover last updated on 16/Dec/25 $$ \\ $$$$\:\:\:\:\:{Differentiate}\:\:\:\:{x}^{{x}^{{x}} } \\ $$$$ \\ $$ Answered by AgniMath last updated on 16/Dec/25 $${y}={x}^{{x}^{{x}}…
Question Number 226821 by Spillover last updated on 16/Dec/25 $${Differentiate}\:\: \\ $$$$\mathrm{20sin}\:\left({x}+\mathrm{3}\right)\mathrm{cos}\:\frac{{x}^{\mathrm{2}} }{\mathrm{2}} \\ $$ Answered by AgniMath last updated on 16/Dec/25 $$\frac{{d}}{{dx}}\:{sin}\left({x}+\mathrm{3}\right)\:=\:{cos}\left({x}+\mathrm{3}\right) \\ $$$$\frac{{d}}{{dx}}\:{cos}\frac{{x}^{\mathrm{2}}…
Question Number 226850 by cherokeesay last updated on 17/Dec/25 Answered by TonyCWX last updated on 17/Dec/25 $${y}\:=\:{x}\left({x}−\mathrm{1}\right)\:\Rightarrow\:{x}\:=\:\mathrm{0}\:\mathrm{or}\:{x}\:=\:\mathrm{1} \\ $$$$\mathrm{A}>\mathrm{0},\:\mathrm{A}=\mathrm{1} \\ $$$$ \\ $$$${x}\left({x}−\mathrm{1}\right)\:=\:\frac{\mathrm{1}}{\mathrm{2}}{x} \\ $$$${x}^{\mathrm{2}}…