Question Number 211367 by mr W last updated on 07/Sep/24 $${solve}\:{for}\:{R}^{+} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} −{kxy}={c}^{\mathrm{2}} \\ $$$${y}^{\mathrm{2}} +{z}^{\mathrm{2}} −{kyz}={a}^{\mathrm{2}} \\ $$$${z}^{\mathrm{2}} +{x}^{\mathrm{2}} −{kzx}={b}^{\mathrm{2}} \\ $$$$\left({k}\:{is}\:{constant}\right)…
Question Number 211377 by jacklau last updated on 07/Sep/24 $$\boldsymbol{\mathrm{The}}\:\boldsymbol{\mathrm{irrational}}\:\boldsymbol{\mathrm{number}}\: \\ $$$$\:^{\mathrm{3}} \sqrt{\:^{\mathrm{3}} \sqrt{\mathrm{2}}−\mathrm{1}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{written}}\:\boldsymbol{\mathrm{as}}\:^{\mathrm{3}} \sqrt{\boldsymbol{\mathrm{p}}}\:+\:^{\mathrm{3}} \sqrt{\boldsymbol{\mathrm{q}}}\:+\:^{\mathrm{3}} \sqrt{\boldsymbol{\mathrm{r}}}\: \\ $$$$\boldsymbol{\mathrm{what}}\:\boldsymbol{\mathrm{is}}\:\boldsymbol{\mathrm{p}},\:\boldsymbol{\mathrm{q}},\:\boldsymbol{\mathrm{r}}\:? \\ $$ Terms of Service Privacy…
Question Number 211340 by Tawa11 last updated on 06/Sep/24 Commented by Frix last updated on 06/Sep/24 $$\mathrm{Question}\:\mathrm{211294} \\ $$ Answered by mr W last updated…
Question Number 211321 by efronzo1 last updated on 06/Sep/24 $$\:\:\:\:\underbrace{\:} \\ $$ Answered by som(math1967) last updated on 06/Sep/24 $$\:\frac{\mathrm{1}+{sin}\theta}{{cos}\theta}={p} \\ $$$$\Rightarrow\frac{\left(\mathrm{1}+{sin}\theta\right)^{\mathrm{2}} }{{cos}^{\mathrm{2}} \theta}={p}^{\mathrm{2}} \\…
Question Number 211323 by mr W last updated on 06/Sep/24 Commented by mr W last updated on 06/Sep/24 $${both}\:{circles}\:{are}\:{concentric}. \\ $$$${find}\:\angle{C}=? \\ $$ Answered by…
Question Number 211365 by JuniorKepler last updated on 06/Sep/24 Answered by mr W last updated on 07/Sep/24 $$\frac{\left({x}+{y}\right)^{{p}} \left({x}+{y}\right)^{{q}} }{{x}^{{p}} {y}^{{q}} }=\mathrm{1} \\ $$$$\left(\mathrm{1}+\frac{{y}}{{x}}\right)^{{p}} \left(\mathrm{1}+\frac{{x}}{{y}}\right)^{{q}}…
Question Number 211344 by Nadirhashim last updated on 06/Sep/24 $$\:\:\:{find}\:\int\frac{\boldsymbol{{dx}}}{\boldsymbol{{sin}}^{\mathrm{3}} \left(\boldsymbol{{x}}\right)\:\boldsymbol{{cos}}^{\mathrm{5}} \left(\boldsymbol{{x}}\right)}\:.\boldsymbol{{dx}}\: \\ $$ Answered by Frix last updated on 06/Sep/24 $$\int\frac{{dx}}{\mathrm{cos}^{\mathrm{5}} \:{x}\:\mathrm{sin}^{\mathrm{3}} \:{x}}=\int\frac{\left(\mathrm{1}+\mathrm{tan}^{\mathrm{2}} \:{x}\right)^{\mathrm{4}}…
Question Number 211345 by a.lgnaoui last updated on 06/Sep/24 $$\mathrm{E}\boldsymbol{\mathrm{valuer}}:\:\:\frac{\boldsymbol{\mathrm{R}}}{\boldsymbol{\mathrm{r}}\mathrm{1}+\boldsymbol{\mathrm{r}}\mathrm{2}} \\ $$ Commented by a.lgnaoui last updated on 06/Sep/24 Terms of Service Privacy Policy Contact:…
Question Number 211330 by RojaTaniya last updated on 06/Sep/24 Answered by mr W last updated on 06/Sep/24 $${say}\:{p}=\frac{{a}}{{b}},\:{q}=\frac{{b}}{{c}},\:{r}=\frac{{c}}{{a}} \\ $$$${pqr}=\mathrm{1} \\ $$$${p}+{q}+{r}=\mathrm{7} \\ $$$$\frac{\mathrm{1}}{{p}}+\frac{\mathrm{1}}{{q}}+\frac{\mathrm{1}}{{r}}=\mathrm{11}\: \\…
Question Number 211331 by efronzo1 last updated on 06/Sep/24 $$\:\:\:\:\:\mathrm{x}=\frac{\sqrt{\mathrm{6}}+\mathrm{2}+\sqrt{\mathrm{3}}+\sqrt{\mathrm{2}}}{\:\sqrt{\mathrm{6}}+\sqrt{\mathrm{3}}−\mathrm{2}−\sqrt{\mathrm{2}}} \\ $$$$\:\:\:\:\mathrm{y}=\frac{\sqrt{\mathrm{6}}−\sqrt{\mathrm{3}}−\mathrm{2}+\sqrt{\mathrm{2}}}{\:\sqrt{\mathrm{6}}−\sqrt{\mathrm{3}}+\mathrm{2}−\sqrt{\mathrm{2}}} \\ $$$$\:\:\:\mathrm{x}^{\mathrm{5}} −\mathrm{y}^{\mathrm{5}} \:=?\: \\ $$ Answered by A5T last updated on 06/Sep/24…