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Author: Tinku Tara

xdx-x-4-please-

Question Number 206721 by ajfour last updated on 23/Apr/24 $$\int\frac{{xdx}}{{x}+\mathrm{4}}=?\:\:\:\:\:\:\:{please} \\ $$ Answered by A5T last updated on 23/Apr/24 $$\frac{{x}}{{x}+\mathrm{4}}=\frac{{x}+\mathrm{4}−\mathrm{4}}{{x}+\mathrm{4}}=\mathrm{1}−\frac{\mathrm{4}}{{x}+\mathrm{4}} \\ $$$$\Rightarrow\int\frac{{x}}{{x}+\mathrm{4}}{dx}=\int\mathrm{1}{dx}−\mathrm{4}\int\frac{\mathrm{1}}{{x}+\mathrm{4}}{dx} \\ $$$$={x}−\mathrm{4}{ln}\mid{x}+\mathrm{4}\mid+{c} \\…

lim-n-cosn-sinn-3-n-4-n-

Question Number 206702 by depressiveshrek last updated on 22/Apr/24 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\sqrt{\mathrm{cos}{n}+\mathrm{sin}{n}−\mathrm{3}^{{n}} +\mathrm{4}^{{n}} } \\ $$ Answered by Frix last updated on 22/Apr/24 $$−\sqrt{\mathrm{2}}\leqslant\mathrm{cos}\:{n}\:+\mathrm{sin}\:{n}\:\leqslant\sqrt{\mathrm{2}} \\ $$$$\forall{a}\in\mathbb{R}:\underset{{n}\rightarrow\infty}…

If-2-1-10-cos-9-i-sin-9-Find-z-5-

Question Number 206695 by hardmath last updated on 22/Apr/24 $$\mathrm{If}\:\:\:\sqrt[{\mathrm{10}}]{\mathrm{2}}\:\left(\mathrm{cos}\:\mathrm{9}°\:+\:\boldsymbol{\mathrm{i}}\:\mathrm{sin}\:\mathrm{9}°\right) \\ $$$$\mathrm{Find}:\:\:\:\boldsymbol{\mathrm{z}}^{\mathrm{5}} \:=\:? \\ $$ Answered by A5T last updated on 22/Apr/24 $${z}=\sqrt[{\mathrm{10}}]{\mathrm{2}}{e}^{{i}\left(\mathrm{9}°\right)} \Rightarrow{z}^{\mathrm{5}} =\sqrt{\mathrm{2}}{e}^{{i}\left(\mathrm{45}°\right)}…

if-f-x-2g-1-x-x-2-and-f-1-x-g-x-x-2-then-f-x-

Question Number 206679 by mathlove last updated on 22/Apr/24 $${if}\:\:\:\:\:\:\:\:\:\:\:\:{f}\left({x}\right)+\mathrm{2}{g}\left(\mathrm{1}−{x}\right)={x}^{\mathrm{2}} \\ $$$${and}\:\:\:\:\:\:\:\:{f}\left(\mathrm{1}−{x}\right)−{g}\left({x}\right)={x}^{\mathrm{2}} \\ $$$${then}\:\:\:\:\:\:\:{f}\left({x}\right)=? \\ $$ Answered by A5T last updated on 22/Apr/24 $${f}\left({x}\right)+\mathrm{2}{g}\left(\mathrm{1}−{x}\right)={x}^{\mathrm{2}} …\left({i}\right)…

Question-206674

Question Number 206674 by 073 last updated on 22/Apr/24 Answered by Frix last updated on 22/Apr/24 $$\Gamma\left({x}\right)=\underset{\mathrm{0}} {\overset{\infty} {\int}}{t}^{{x}−\mathrm{1}} \mathrm{e}^{−{t}} {dt} \\ $$$$\frac{{d}\Gamma\left({x}\right)}{{dx}}=\Gamma'\left({x}\right)=\underset{\mathrm{0}} {\overset{\infty} {\int}}{t}^{{x}−\mathrm{1}}…