Question Number 206542 by luciferit last updated on 18/Apr/24 Answered by lepuissantcedricjunior last updated on 18/Apr/24 $$\int\left(\mathrm{3}\boldsymbol{{x}}+\mathrm{5}\right)\boldsymbol{{arctan}}\left(\boldsymbol{{x}}\right)\boldsymbol{{dx}}=\boldsymbol{{k}} \\ $$$$\begin{cases}{\boldsymbol{{u}}=\boldsymbol{{arctan}}\left(\boldsymbol{{x}}\right)}\\{\boldsymbol{{v}}'=\left(\mathrm{3}\boldsymbol{{x}}+\mathrm{5}\right)}\end{cases}=>\begin{cases}{\boldsymbol{{u}}'=\frac{\mathrm{1}}{\mathrm{1}+\boldsymbol{{x}}^{\mathrm{2}} }}\\{\boldsymbol{{v}}=\frac{\mathrm{3}}{\mathrm{2}}\boldsymbol{{x}}^{\mathrm{2}} +\mathrm{5}\boldsymbol{{x}}}\end{cases} \\ $$$$\boldsymbol{{k}}=\left(\frac{\mathrm{3}}{\mathrm{2}}\boldsymbol{{x}}^{\mathrm{2}} +\mathrm{5}\boldsymbol{{x}}\right)\boldsymbol{{arctan}}\left(\boldsymbol{{x}}\right)−\frac{\mathrm{3}}{\mathrm{2}}\int\frac{\boldsymbol{{x}}^{\mathrm{2}} +\mathrm{1}+\frac{\mathrm{10}}{\mathrm{3}}\boldsymbol{{x}}−\mathrm{1}}{\mathrm{1}+\boldsymbol{{x}}^{\mathrm{2}}…
Question Number 206543 by luciferit last updated on 18/Apr/24 Answered by lepuissantcedricjunior last updated on 18/Apr/24 $$\int\frac{\mathrm{3}+\mathrm{2}\sqrt{\boldsymbol{{x}}}}{\mathrm{4}+\sqrt{\boldsymbol{{x}}}}\boldsymbol{{dx}}=\int\frac{\mathrm{2}\left(\mathrm{4}+\sqrt{{x}}\right)−\mathrm{5}}{\mathrm{4}+\sqrt{\boldsymbol{{x}}}}\boldsymbol{{dx}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\mathrm{2}\boldsymbol{{x}}−\left\{\mathrm{5}\int\frac{\boldsymbol{{dx}}}{\mathrm{4}+\sqrt{\boldsymbol{{x}}}}\:\:\:\:\boldsymbol{{x}}=\boldsymbol{{t}}^{\mathrm{2}} \Leftrightarrow\boldsymbol{{dx}}=\mathrm{2}\boldsymbol{{tdt}}\right\} \\ $$$$\:\:\:\:\:\:\:\:\:\:=\mathrm{2}\boldsymbol{{x}}−\left\{\mathrm{10}\int\left(\mathrm{1}−\frac{\mathrm{4}}{\mathrm{4}+\boldsymbol{{t}}}\right)\boldsymbol{{dt}}\right\} \\ $$$$\:\:\:\:\:\:\:\:\:\:=\mathrm{2}\boldsymbol{{x}}−\mathrm{10}\sqrt{\boldsymbol{{x}}}+\mathrm{40}\boldsymbol{{ln}}\left(\mathrm{4}+\sqrt{\boldsymbol{{x}}}\right)+\boldsymbol{{c}} \\…
Question Number 206568 by universe last updated on 18/Apr/24 Answered by Berbere last updated on 19/Apr/24 $$\frac{{x}}{{n}}={y}\:\:{A}\left({n}\right)=\int_{\mathrm{0}} ^{{n}} \left(\frac{\mathrm{2}{nx}}{{x}^{\mathrm{2}} +{n}^{\mathrm{2}} }\right)^{{n}} {dx}={n}\int_{\mathrm{0}} ^{\mathrm{1}} \left(\frac{\mathrm{2}{y}}{\mathrm{1}+{y}^{\mathrm{2}} }\right)^{{n}}…
Question Number 206536 by cortano21 last updated on 18/Apr/24 $$\:\:\:\:\underline{\underbrace{\lessdot}\cancel{} }\underbrace{\nsupseteqq\spadesuit\left[}\mathrm{2}^{{x}} \:\mathrm{sin}\:\left(\sqrt{\mathrm{4}−\mathrm{2}^{{x}+\mathrm{2}} }\:\right)\right. \\ $$ Commented by Frix last updated on 18/Apr/24 $$\mathrm{Simply}\:\mathrm{use}\:{t}=\sqrt{\mathrm{1}−\mathrm{2}^{{x}} } \\…
Question Number 206537 by necx122 last updated on 18/Apr/24 $$\int\frac{{x}^{\mathrm{4}} −\mathrm{1}}{{x}^{\mathrm{2}} \sqrt{{x}^{\mathrm{4}} +{x}^{\mathrm{2}} +\mathrm{1}}}{dx} \\ $$ Answered by Berbere last updated on 18/Apr/24 $$=\int\frac{{x}\left(\mathrm{4}{x}^{\mathrm{3}} +\mathrm{2}{x}\right)−\mathrm{2}{x}^{\mathrm{4}}…
Question Number 206571 by mr W last updated on 19/Apr/24 Answered by cortano21 last updated on 19/Apr/24 $$\:\:\underline{\:} \\ $$ Commented by mr W last…
Question Number 206511 by naka3546 last updated on 17/Apr/24 Commented by mr W last updated on 17/Apr/24 $${i}\:{got}\:\mathrm{17178}. \\ $$ Commented by A5T last updated…
Question Number 206522 by MrGHK last updated on 17/Apr/24 Answered by Berbere last updated on 17/Apr/24 $${u}'={xln}^{\mathrm{2}} \left({x}\right)\Rightarrow{u}=\frac{\mathrm{1}}{\mathrm{2}}\left({x}^{\mathrm{2}} {ln}^{\mathrm{2}} \left({x}\right)−{x}^{\mathrm{2}} {ln}\left({x}\right)+\frac{{x}^{\mathrm{2}} }{\mathrm{2}}\right) \\ $$$${v}={Li}_{\mathrm{2}} \left(\frac{\mathrm{1}+{x}}{{x}}\right);{v}'=−\frac{\mathrm{1}}{{x}^{\mathrm{2}}…
Question Number 206532 by necx122 last updated on 17/Apr/24 $${Find}\:{the}\:{nth}\:{term}\:{of}\:{the}\:{sequence} \\ $$$$\mathrm{0},\mathrm{3},\mathrm{8},\mathrm{15},\mathrm{24},…… \\ $$ Answered by Berbere last updated on 17/Apr/24 $${Impossibl} \\ $$$${there}\:{are}\left[{infinity}\:{way}\:\right. \\…
Question Number 206514 by cortano21 last updated on 17/Apr/24 $$\:{In}\:{this}\:{covid}\:−\mathrm{19}\:{pandemic},\:{it}\:{is}\: \\ $$$$\:{known}\:{that}\:{are}\:\mathrm{5},\mathrm{667},\mathrm{355}\:{confirmed}\: \\ $$$$\:{cases}\:{out}\:{of}\:\mathrm{273},\mathrm{500},\mathrm{000}\:{in}\:{X}\:{country} \\ $$$$\:{population}\:{based}\:{WHO}.\: \\ $$$$\:{One}\:{of}\:{the}\:{equipment}\:{to}\:{test}\:{the} \\ $$$$\:{covid}−\mathrm{19}\:{is}\:{GeNose}\:{C}\mathrm{19}−{S}\:{developed} \\ $$$$\:{by}\:{UGM}.\:{GeNose}\:{C}\mathrm{19}−{S}\:{is}\:{a}\:{rapid} \\ $$$$\:{screening}\:{equipment}\:{for}\:{Sars}−{CoV}\mathrm{2} \\…