Question Number 220628 by Spillover last updated on 17/May/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 220693 by hardmath last updated on 17/May/25 Commented by mr W last updated on 18/May/25 $${x}=\mathrm{6}? \\ $$ Commented by hardmath last updated…
Question Number 220694 by hardmath last updated on 17/May/25 Commented by hardmath last updated on 17/May/25 $$\mathrm{C}\left(\mathrm{xy}\right)\:=\:? \\ $$ Answered by vnm last updated on…
Question Number 220630 by Mingma last updated on 17/May/25 Answered by mr W last updated on 17/May/25 Commented by mr W last updated on 17/May/25…
Question Number 220656 by Tawa11 last updated on 17/May/25 Commented by Tawa11 last updated on 17/May/25 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{shaded}. \\ $$ Answered by Ghisom last updated on…
Question Number 220625 by Spillover last updated on 17/May/25 Answered by mr W last updated on 17/May/25 $${for}\:{the}\:{remaining}\:\mathrm{4}\:{doors}\:{he}\:{needs} \\ $$$${additional}\:{paint}\:{which}\:{can}\:{only}\:{be}\: \\ $$$${blue},\:{green}\:{or}\:{yellow}. \\ $$$$\left.\mathrm{1}\right)\:{color}\:{for}\:{addtional}\:{paint}\:{is}\:{blue} \\…
Question Number 220626 by Spillover last updated on 17/May/25 Answered by mr W last updated on 17/May/25 $$\left.\mathrm{1}\right)\:\mathrm{4}\:{couples}\:{in}\:{one}\:{compartment} \\ $$$$\Rightarrow\mathrm{2}\:{ways} \\ $$$$\left.\mathrm{2}\right)\:\mathrm{3}\:{couples}\:{in}\:{one}\:{compartment} \\ $$$$\mathrm{2}×{C}_{\mathrm{4}} ^{\mathrm{3}}…
Question Number 220627 by Spillover last updated on 17/May/25 Answered by mr W last updated on 17/May/25 $$\left.\mathrm{1}\right)\:{no}\:{egg}\:{in}\:{all}\:{three}\:{days}: \\ $$$$\mathrm{3}!=\mathrm{6}\:{ways} \\ $$$$\left.\mathrm{2}\right)\:{egg}\:{in}\:{one}\:{day}: \\ $$$$\mathrm{3}×\mathrm{3}×\mathrm{3}×\mathrm{2}=\mathrm{54}\:{ways} \\…
Question Number 220652 by SdC355 last updated on 17/May/25 $$\mathrm{Show}\:\mathrm{that} \\ $$$$\int_{\mathrm{0}} ^{\:\infty} \:\frac{{e}^{−{st}} }{\:\sqrt{{t}^{\mathrm{2}} +\mathrm{1}}}\:\mathrm{d}{t}=\frac{\mathrm{1}}{\mathrm{2}}\pi\left(\boldsymbol{\mathrm{H}}_{\mathrm{0}} ^{\:} \left({s}\right)−{Y}_{\mathrm{0}} \left({s}\right)\right)\:,\:{s}\in\mathbb{R}\backslash\left\{\mathrm{0}\right\} \\ $$ Terms of Service Privacy…
Question Number 220655 by MrGaster last updated on 17/May/25 Terms of Service Privacy Policy Contact: info@tinkutara.com