Question Number 211340 by Tawa11 last updated on 06/Sep/24 Commented by Frix last updated on 06/Sep/24 $$\mathrm{Question}\:\mathrm{211294} \\ $$ Answered by mr W last updated…
Question Number 211321 by efronzo1 last updated on 06/Sep/24 $$\:\:\:\:\underbrace{\:} \\ $$ Answered by som(math1967) last updated on 06/Sep/24 $$\:\frac{\mathrm{1}+{sin}\theta}{{cos}\theta}={p} \\ $$$$\Rightarrow\frac{\left(\mathrm{1}+{sin}\theta\right)^{\mathrm{2}} }{{cos}^{\mathrm{2}} \theta}={p}^{\mathrm{2}} \\…
Question Number 211323 by mr W last updated on 06/Sep/24 Commented by mr W last updated on 06/Sep/24 $${both}\:{circles}\:{are}\:{concentric}. \\ $$$${find}\:\angle{C}=? \\ $$ Answered by…
Question Number 211365 by JuniorKepler last updated on 06/Sep/24 Answered by mr W last updated on 07/Sep/24 $$\frac{\left({x}+{y}\right)^{{p}} \left({x}+{y}\right)^{{q}} }{{x}^{{p}} {y}^{{q}} }=\mathrm{1} \\ $$$$\left(\mathrm{1}+\frac{{y}}{{x}}\right)^{{p}} \left(\mathrm{1}+\frac{{x}}{{y}}\right)^{{q}}…
Question Number 211344 by Nadirhashim last updated on 06/Sep/24 $$\:\:\:{find}\:\int\frac{\boldsymbol{{dx}}}{\boldsymbol{{sin}}^{\mathrm{3}} \left(\boldsymbol{{x}}\right)\:\boldsymbol{{cos}}^{\mathrm{5}} \left(\boldsymbol{{x}}\right)}\:.\boldsymbol{{dx}}\: \\ $$ Answered by Frix last updated on 06/Sep/24 $$\int\frac{{dx}}{\mathrm{cos}^{\mathrm{5}} \:{x}\:\mathrm{sin}^{\mathrm{3}} \:{x}}=\int\frac{\left(\mathrm{1}+\mathrm{tan}^{\mathrm{2}} \:{x}\right)^{\mathrm{4}}…
Question Number 211345 by a.lgnaoui last updated on 06/Sep/24 $$\mathrm{E}\boldsymbol{\mathrm{valuer}}:\:\:\frac{\boldsymbol{\mathrm{R}}}{\boldsymbol{\mathrm{r}}\mathrm{1}+\boldsymbol{\mathrm{r}}\mathrm{2}} \\ $$ Commented by a.lgnaoui last updated on 06/Sep/24 Terms of Service Privacy Policy Contact:…
Question Number 211330 by RojaTaniya last updated on 06/Sep/24 Answered by mr W last updated on 06/Sep/24 $${say}\:{p}=\frac{{a}}{{b}},\:{q}=\frac{{b}}{{c}},\:{r}=\frac{{c}}{{a}} \\ $$$${pqr}=\mathrm{1} \\ $$$${p}+{q}+{r}=\mathrm{7} \\ $$$$\frac{\mathrm{1}}{{p}}+\frac{\mathrm{1}}{{q}}+\frac{\mathrm{1}}{{r}}=\mathrm{11}\: \\…
Question Number 211331 by efronzo1 last updated on 06/Sep/24 $$\:\:\:\:\:\mathrm{x}=\frac{\sqrt{\mathrm{6}}+\mathrm{2}+\sqrt{\mathrm{3}}+\sqrt{\mathrm{2}}}{\:\sqrt{\mathrm{6}}+\sqrt{\mathrm{3}}−\mathrm{2}−\sqrt{\mathrm{2}}} \\ $$$$\:\:\:\:\mathrm{y}=\frac{\sqrt{\mathrm{6}}−\sqrt{\mathrm{3}}−\mathrm{2}+\sqrt{\mathrm{2}}}{\:\sqrt{\mathrm{6}}−\sqrt{\mathrm{3}}+\mathrm{2}−\sqrt{\mathrm{2}}} \\ $$$$\:\:\:\mathrm{x}^{\mathrm{5}} −\mathrm{y}^{\mathrm{5}} \:=?\: \\ $$ Answered by A5T last updated on 06/Sep/24…
Question Number 211310 by hardmath last updated on 05/Sep/24 $$\mathrm{Find}: \\ $$$$\mathrm{LCD}\left(\mathrm{2}^{\mathrm{100}} \:−\:\mathrm{1}\:\:;\:\:\mathrm{2}^{\mathrm{120}} \:−\:\mathrm{1}\right)\:=\:? \\ $$ Answered by A5T last updated on 05/Sep/24 $${What}\:{is}\:{LCD}?\:{Do}\:{you}\:{mean}\:{GCD}\:{or}\:{LCM}? \\…
Question Number 211294 by Jubr last updated on 05/Sep/24 Commented by a.lgnaoui last updated on 05/Sep/24 Commented by Ghisom last updated on 05/Sep/24 $$\mathrm{just}\:\mathrm{saying}:\:\mathrm{it}'\mathrm{s}\:\mathrm{not}\:\mathrm{convex} \\…