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Author: Tinku Tara

let-d-2-y-dx-2-p-x-dy-dx-q-x-y-0-x-R-where-p-x-and-q-x-are-continuous-function-if-y-1-sinx-2cosx-and-y-2-2sinx-cosx-are-L-I-linearly-independent-solution-then-

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Question Number 206142 by universe last updated on 07/Apr/24 $$\:\:\:\:\mathrm{let}\:\:\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }+{p}\left({x}\right)\frac{{dy}}{{dx}}+{q}\left({x}\right){y}=\mathrm{0}\:,\:{x}\in\mathbb{R}\:\mathrm{where}\: \\ $$$$\:\:\:\:{p}\left({x}\right)\:\mathrm{and}\:{q}\left({x}\right)\:\mathrm{are}\:\mathrm{continuous}\:\mathrm{function}\:\mathrm{if} \\ $$$$\:\:\:\:{y}_{\mathrm{1}} =\:\mathrm{sin}{x}−\mathrm{2cos}{x}\:{and}\:{y}_{\mathrm{2}} \:=\:\mathrm{2sin}{x}\:+\mathrm{cos}{x} \\ $$$$\:\:\:\:\mathrm{are}\:{L}.{I}\:\left(\mathrm{linearly}\:\mathrm{independent}\right)\:\mathrm{solution} \\ $$$$\:\:\:\:\:\mathrm{then}\:\:\mid\mathrm{4}{p}\left(\mathrm{0}\right)+\mathrm{2}{q}\left(\mathrm{1}\right)\mid\:=\:?\:\:\: \\ $$ Answered…

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Question-206136

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Question Number 206136 by cortano21 last updated on 07/Apr/24 Answered by A5T last updated on 07/Apr/24 $${f}\left({f}\left({f}\left({f}\left({x}\right)\right)\right)\right)=\left[{f}\left({x}\right)\right]^{\mathrm{2}} −\mathrm{3}\left[{f}\left({x}\right)\right]+\mathrm{4}={f}\left({x}^{\mathrm{2}} −\mathrm{3}{x}+\mathrm{4}\right) \\ $$$$\left[{f}\left(\mathrm{2}\right)\right]^{\mathrm{2}} −\mathrm{3}\left[{f}\left(\mathrm{2}\right)\right]+\mathrm{4}={f}\left(\mathrm{2}\right)\Rightarrow\left[{f}\left(\mathrm{2}\right)\right]^{\mathrm{2}} −\mathrm{4}{f}\left(\mathrm{2}\right)+\mathrm{4}=\mathrm{0} \\ $$$$\left[{f}\left(\mathrm{2}\right)−\mathrm{2}\right]^{\mathrm{2}}…

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Question-206104

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Question Number 206104 by cortano21 last updated on 07/Apr/24 $$\:\:\:\:\downharpoonleft\underline{\:} \\ $$ Answered by dimentri last updated on 07/Apr/24 $$\:\:\mathrm{7}^{−\mathrm{a}} =\:\mathrm{3}^{−\mathrm{b}} =\:\mathrm{2}^{−\mathrm{c}} =\mathrm{5}^{−\mathrm{d}} =\:\mathrm{m} \\…

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Question Number 206107 by MaruMaru last updated on 07/Apr/24 $$\mathrm{can}\:\mathrm{you}\:\mathrm{guy}\:\mathrm{explian}\:\mathrm{why} \\ $$$$\mathrm{we}\:\mathrm{need}\:\mathrm{a}\:\mathrm{eighgen}\:\mathrm{value}\:\mathrm{eighgen}\:\mathrm{vector} \\ $$$$\mathrm{and}\:\mathrm{mean}?? \\ $$$$\mathrm{such}\:\mathrm{as}\:\mathrm{A}\boldsymbol{\mathrm{v}}=\boldsymbol{\lambda\mathrm{v}} \\ $$$$ \\ $$ Commented by mr W last…

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