Question Number 205685 by MathedUp last updated on 27/Mar/24 Answered by TonyCWX08 last updated on 27/Mar/24 $$\frac{\mathrm{1}}{\mathrm{10}}{g} \\ $$ Commented by MathedUp last updated on…
Question Number 205680 by mnjuly1970 last updated on 27/Mar/24 $$ \\ $$$$\:\:\:\:\:\:\:\:\:{solve}\: \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\lfloor{x}\:\rfloor\:+\:\lfloor\:{x}^{\mathrm{2}} \rfloor\:=\:\lfloor\:{x}^{\mathrm{3}} \:\rfloor \\ $$$$ \\ $$ Answered by Frix…
Question Number 205681 by naka3546 last updated on 27/Mar/24 Answered by mr W last updated on 27/Mar/24 $${a}=\mathrm{1}\:{cm} \\ $$$${R}=\frac{\mathrm{1}}{\mathrm{3}}×\frac{\sqrt{\mathrm{3}}{a}}{\mathrm{2}}=\frac{\sqrt{\mathrm{3}}{a}}{\mathrm{6}} \\ $$$${r}=\frac{\sqrt{\mathrm{3}}{b}}{\mathrm{6}} \\ $$$$\frac{{b}}{{a}}=\frac{\frac{\sqrt{\mathrm{3}}{a}}{\mathrm{2}}−\mathrm{2}{R}}{\frac{\sqrt{\mathrm{3}}{a}}{\mathrm{2}}}=\frac{\mathrm{1}}{\mathrm{3}} \\…
Question Number 205682 by naka3546 last updated on 27/Mar/24 Commented by naka3546 last updated on 28/Mar/24 $$\mathrm{Thank}\:\mathrm{you} \\ $$ Commented by Frix last updated on…
Question Number 205683 by cortano12 last updated on 27/Mar/24 $$\:\:\:\:\: \\ $$ Commented by mr W last updated on 27/Mar/24 $$\mathrm{1632}×\mathrm{3}!=\mathrm{9792} \\ $$$${all}\:{options}\:{given}\:{are}\:{wrong}. \\ $$…
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Question Number 205660 by marie last updated on 26/Mar/24 Answered by Skabetix last updated on 26/Mar/24 $$\mathrm{E}{xercice}\:{n}°\mathrm{4} \\ $$$$\left.\mathrm{1}\right)\:{D}'{apres}\:{le}\:{theoreme}\:{de}\:{Pythagore}\:: \\ $$$${BC}^{\mathrm{2}} ={AC}^{\mathrm{2}} +{AB}^{\mathrm{2}} \\ $$$$\Leftrightarrow{BC}^{\mathrm{2}}…
Question Number 205631 by Lindemann last updated on 26/Mar/24 Answered by A5T last updated on 26/Mar/24 $${If}\:{angle}\:{between}\:{x}\:{and}\:{x}+\mathrm{17}\:{is}\:\mathrm{90}° \\ $$$$\left({x}+\mathrm{18}\right)^{\mathrm{2}} ={x}^{\mathrm{2}} +\left({x}+\mathrm{17}\right)^{\mathrm{2}} \Rightarrow{x}=\mathrm{7} \\ $$$$\frac{\mathrm{7}×\mathrm{24}}{\mathrm{2}}={r}\left(\frac{\mathrm{7}+\mathrm{24}+\mathrm{25}}{\mathrm{2}}\right)\Rightarrow{r}=\mathrm{3} \\…
Question Number 205656 by SANOGO last updated on 26/Mar/24 Answered by TheHoneyCat last updated on 31/Mar/24 $$\left(\mathrm{2}\right)\Rightarrow\left(\mathrm{1}\right) \\ $$$$\mathrm{Soit}\:{c}\in\mathbb{R}^{\ast} \:\mathrm{tel}\:\mathrm{que}\:\forall{x}\in{X}\:\:\mid\mid{T}\left({x}\right)\mid\mid_{{Y}} \:\geqslant{c}\mid\mid{x}\mid\mid_{{X}} \\ $$$$\mathrm{Soit}\:\left({x},{x}'\right)\in{X}^{\mathrm{2}} \\ $$$$\mid\mid{T}\left({x}\right)−{T}\left({x}'\right)\mid\mid…
Question Number 205657 by mnjuly1970 last updated on 26/Mar/24 Answered by mr W last updated on 26/Mar/24 $${small}\:{square}:\:{a}×{a}=\mathrm{6}×\mathrm{6} \\ $$$${big}\:{square}:\:{b}×{b} \\ $$$${area}\:{of}\:{triangle}: \\ $$$${A}_{\mathrm{1}} +{A}_{\mathrm{2}}…