Question Number 219731 by Nescio last updated on 01/May/25 Answered by breniam last updated on 03/May/25 $$=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{sin}\left({x}^{\mathrm{2}} \right)}{{x}^{\mathrm{2}} }×\frac{{x}}{\mathrm{log}\left(\mathrm{1}+\mathrm{2}{x}\right)}×\mathrm{tan}\left({x}\right)={L} \\ $$$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\mathrm{sin}\left({x}^{\mathrm{2}} \right)}{{x}^{\mathrm{2}} }=\mathrm{1}…
Question Number 219724 by Nicholas666 last updated on 01/May/25 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{prove}; \\ $$$$\:\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\prod}}\:\frac{\left(\mathrm{2}{n}+\mathrm{1}\right)^{\mathrm{3}} −\mathrm{3}\left(\mathrm{2}{n}+\mathrm{1}\right)+\mathrm{2}}{\left(\mathrm{2}{n}+\mathrm{1}\right)^{\mathrm{3}} }\:=\:\frac{\pi}{\mathrm{6}} \\ $$$$ \\ $$ Answered by nothing48 last updated…
Question Number 219789 by Firhad last updated on 01/May/25 Commented by Firhad last updated on 02/May/25 $${can}\:{you}\:{help}\:{me} \\ $$ Commented by mr W last updated…
Question Number 219725 by Nicholas666 last updated on 01/May/25 Commented by Nicholas666 last updated on 01/May/25 $$\:\:\:\:\:{prove}\:{MN}\mid\mid{AD} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 219784 by Spillover last updated on 01/May/25 Answered by Spillover last updated on 02/May/25 Answered by JV2BTC last updated on 02/May/25 $${why}\:{not} \\…
Question Number 219720 by Spillover last updated on 01/May/25 Answered by mr W last updated on 01/May/25 $$\frac{{R}_{\mathrm{2}} }{{x}}=\frac{{R}_{\mathrm{1}} +{R}_{\mathrm{2}} }{{a}}=\frac{{R}_{\mathrm{2}} +{R}_{\mathrm{3}} }{{b}}={k},\:{say} \\ $$$$\Rightarrow{R}_{\mathrm{2}}…
Question Number 219785 by Spillover last updated on 01/May/25 Answered by Spillover last updated on 02/May/25 Answered by Spillover last updated on 02/May/25 Answered by…
Question Number 219721 by Spillover last updated on 01/May/25 Answered by mr W last updated on 01/May/25 Commented by mr W last updated on 01/May/25…
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Question Number 219722 by Spillover last updated on 01/May/25 Answered by mr W last updated on 01/May/25 Commented by mr W last updated on 01/May/25…