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Question Number 209137 by mr W last updated on 02/Jul/24 Answered by kapoorshah last updated on 02/Jul/24 $${Math}\:{Booster} \\ $$ Answered by cherokeesay last updated…
Question Number 209166 by Tawa11 last updated on 02/Jul/24 Answered by mr W last updated on 02/Jul/24 $$\left({a}\right) \\ $$$${p}=\left(\frac{\mathrm{3}}{\mathrm{4}}\right)^{\mathrm{3}} =\mathrm{0}.\mathrm{42} \\ $$$$\left({b}\right) \\ $$$${p}={C}_{\mathrm{2}}…
Question Number 209167 by lmcp1203 last updated on 02/Jul/24 $${please}\:{convert}\:\:\mathrm{2531}_{\left(\mathrm{5000}\right)\:} {to}\:\:{base}\:\mathrm{5002}.\:\:{thanks}.\:\: \\ $$ Answered by mr W last updated on 03/Jul/24 $$\mathrm{2531}_{\left(\mathrm{5000}\right)} =\mathrm{2}×\mathrm{5000}^{\mathrm{3}} +\mathrm{5}×\mathrm{5000}^{\mathrm{2}} +\mathrm{3}×\mathrm{5000}+\mathrm{1}…
Question Number 209128 by Spillover last updated on 02/Jul/24 Answered by A5T last updated on 02/Jul/24 $${The}\:{length}\:{of}\:{the}\:{diagonal}\:{of}\:{the}\:{square}=\mathrm{2}{r} \\ $$$$\Rightarrow{s}^{\mathrm{2}} +{s}^{\mathrm{2}} =\mathrm{4}{r}^{\mathrm{2}} \Rightarrow\mathrm{2}{s}^{\mathrm{2}} =\mathrm{4}{r}^{\mathrm{2}} \Rightarrow{s}^{\mathrm{2}} =\mathrm{2}{r}^{\mathrm{2}}…
Question Number 209161 by Spillover last updated on 02/Jul/24 Commented by klipto last updated on 03/Jul/24 $$ \\ $$$$\boldsymbol{\mathrm{F}}_{\boldsymbol{\mathrm{net}}} =−\left(\boldsymbol{\mathrm{F}}_{\mathrm{g}} +\boldsymbol{\mathrm{P}}\right) \\ $$$$\boldsymbol{\mathrm{ma}}=−\left(\boldsymbol{\mathrm{mg}}+\mathrm{0}.\mathrm{2}\boldsymbol{\mathrm{v}}^{\mathrm{2}} \right) \\…
Question Number 209129 by Adeyemi889 last updated on 02/Jul/24 Answered by A5T last updated on 02/Jul/24 $$\frac{{x}^{\mathrm{3}} +\mathrm{3}}{{x}^{\mathrm{2}} −\mathrm{1}}=\frac{{x}\left({x}^{\mathrm{2}} −\mathrm{1}\right)+{x}+\mathrm{3}}{{x}^{\mathrm{2}} −\mathrm{1}}={x}+\frac{{x}+\mathrm{3}}{{x}^{\mathrm{2}} −\mathrm{1}} \\ $$$$\frac{{x}+\mathrm{3}}{{x}^{\mathrm{2}} −\mathrm{1}}=\frac{{A}}{{x}−\mathrm{1}}+\frac{{B}}{{x}+\mathrm{1}}\Rightarrow{x}+\mathrm{3}=\left({A}+{B}\right){x}+{A}−{B}…
Question Number 209162 by dr1001sa last updated on 02/Jul/24 $$ \\ $$Cyclic quadrilateral ABCD is inscribed in circle. Point S is intersection of diagonals AC…
Question Number 209131 by mahdipoor last updated on 02/Jul/24 $${prove}\:: \\ $$$${curve}\:\begin{cases}{{x}\left({t}\right)=\frac{{a}+{r}.{cos}\left({t}\right)}{{a}^{\mathrm{2}} +{r}^{\mathrm{2}} +\mathrm{2}{ar}.{cos}\left({t}\right)}}\\{{y}\left({t}\right)=\frac{{r}.{sin}\left({t}\right)}{{a}^{\mathrm{2}} +{r}^{\mathrm{2}} +\mathrm{2}{ar}.{cos}\left({t}\right)}}\end{cases}\:\:\:\:\mathrm{0}\leqslant{t}\leqslant\mathrm{2}\pi \\ $$$${is}\:{circle}\:,\:{find}\:{center}\:\&\:{radius} \\ $$ Answered by Frix last updated…