Question Number 203955 by mr W last updated on 03/Feb/24 $$\mathrm{50\%}+\mathrm{50\%}=\mathrm{75\%}? \\ $$ Commented by mr W last updated on 03/Feb/24 Commented by Rasheed.Sindhi last…
Question Number 203980 by Davidtim last updated on 03/Feb/24 $$\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\frac{{ax}^{\mathrm{2}} +{bx}+\mathrm{6}}{{x}^{\mathrm{2}} −{x}−\mathrm{2}}=\mathrm{10}\:\:;\:\:\:{find}\:\:{a}=?\:\wedge\:{b}=? \\ $$ Answered by AST last updated on 03/Feb/24 $$\frac{{a}\left({x}^{\mathrm{2}} −{x}−\mathrm{2}\right)+\left({b}+{a}\right){x}+\mathrm{6}+\mathrm{2}{a}}{{x}^{\mathrm{2}} −{x}−\mathrm{2}}=\mathrm{10}…
Question Number 204005 by hardmath last updated on 03/Feb/24 $$\mathrm{Find}: \\ $$$$\mathrm{cos44}°\:−\:\mathrm{cos84}°\:+\:\mathrm{ctg45}°\:=\:? \\ $$ Commented by Frix last updated on 04/Feb/24 $$\mathrm{We}\:\mathrm{cannot}\:\mathrm{get}\:\mathrm{an}\:\mathrm{expression}\:\mathrm{for}\:\mathrm{cos}\:\mathrm{44}°. \\ $$ Answered…
Question Number 203975 by witcher3 last updated on 03/Feb/24 $$\mathrm{Let}\:\mathrm{P}\in\mathbb{C}\left[\mathrm{X}\right] \\ $$$$\mathrm{p}\left(\mathrm{x}^{\mathrm{2}} +\mathrm{1}\right)=\mathrm{p}^{\mathrm{2}} \left(\mathrm{x}\right)+\mathrm{1} \\ $$$$\mathrm{p}\left(\mathrm{0}\right)=\mathrm{0} \\ $$$$\mathrm{determin}\:\mathrm{all}\:\mathrm{polynom}\: \\ $$ Commented by Rasheed.Sindhi last updated…
Question Number 203969 by mr W last updated on 03/Feb/24 Answered by Rasheed.Sindhi last updated on 03/Feb/24 $$?={x} \\ $$$$\bigtriangleup\mathrm{ABC}\sim\bigtriangleup\mathrm{ADE} \\ $$$$\frac{\mathrm{3}}{{r}}=\frac{\mathrm{4}}{\mathrm{4}−{r}}=\frac{\mathrm{5}}{{x}+{r}}\Rightarrow\mathrm{4}{r}=\mathrm{12}−\mathrm{3}{r}\Rightarrow{r}=\frac{\mathrm{12}}{\mathrm{7}} \\ $$$$\frac{\mathrm{3}}{{r}}=\frac{\mathrm{5}}{{x}+{r}}\Rightarrow\frac{\mathrm{3}}{\frac{\mathrm{12}}{\mathrm{7}}}=\frac{\mathrm{5}}{{x}+\frac{\mathrm{12}}{\mathrm{7}}} \\…
Question Number 203970 by CrispyXYZ last updated on 03/Feb/24 $$\mathrm{In}\:\mathrm{a}\:\mathrm{convex}\:\mathrm{quadrilateral}\:{ABCD}\:,\: \\ $$$$\mathrm{if}\:\mathrm{sin}{A}\:=\:\mathrm{cos}{B},\:\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{range}\:\mathrm{of} \\ $$$${S}\:=\:\mathrm{3sin}{A}\:+\:\mathrm{4sin}{B}\:+\:\mathrm{5}\sqrt{\mathrm{2}}\mathrm{sin}{C}\:+\:\mathrm{5}\sqrt{\mathrm{2}}\mathrm{sin}{D}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 203933 by liuxinnan last updated on 02/Feb/24 $${a}^{\mathrm{2}} +{b}^{\mathrm{2}} +\mathrm{2}{c}^{\mathrm{2}} =\mathrm{22} \\ $$$${prove}\:{a}+\mathrm{2}{b}+{c}\leqslant\mathrm{11} \\ $$ Answered by York12 last updated on 02/Feb/24 $$\left({a}+\mathrm{2}{b}+{c}\right)^{\mathrm{2}}…
Question Number 203935 by mathlove last updated on 02/Feb/24 $$\frac{{cos}\frac{{x}}{\mathrm{3}}+{sin}\:\frac{{x}}{\mathrm{3}}}{{cos}\:\frac{{x}}{\mathrm{3}}−{sin}\:\frac{{x}}{\mathrm{3}}}=? \\ $$ Answered by esmaeil last updated on 02/Feb/24 $$=\frac{\sqrt{\mathrm{2}}{sin}\left(\frac{{x}}{\mathrm{3}}+\frac{\pi}{\mathrm{4}}\right)}{\:\sqrt{\mathrm{2}}{cos}\left(\frac{{x}}{\mathrm{3}}+\frac{\pi}{\mathrm{4}}\right)}={tan}\left(\frac{\pi}{\mathrm{4}}+\frac{{x}}{\mathrm{3}}\right) \\ $$ Answered by AST…
Question Number 203921 by Davidtim last updated on 02/Feb/24 $${prove}\:{that}\:\mathrm{0}^{\mathrm{0}} =\mathrm{1} \\ $$ Commented by malwan last updated on 02/Feb/24 $${this}\:{is}\:{indeterminate}\:{form} \\ $$$${but}\:\underset{{x}\rightarrow\mathrm{0}^{+} } {{lim}}\:{x}^{{x}}…
Question Number 203923 by meheraj last updated on 02/Feb/24 Terms of Service Privacy Policy Contact: info@tinkutara.com