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Question Number 218202 by Rojarani last updated on 01/Apr/25 Commented by Frix last updated on 01/Apr/25 $$\mathrm{I}\:\mathrm{think}\:\mathrm{it}'\mathrm{s}\:\mathrm{9}−\mathrm{4}\sqrt{\mathrm{5}} \\ $$ Commented by Rojarani last updated on…
Question Number 218196 by mnjuly1970 last updated on 01/Apr/25 $$ \\ $$$$ \\ $$$$\:\:\:\:\mathrm{lim}\:_{\mathrm{n}\rightarrow\infty} \frac{\mathrm{1}}{{n}}\:\left(\:\frac{\left(\mathrm{2}{n}\right)!}{{n}!}\:\right)^{\frac{\mathrm{1}}{{n}}} =\:?\:\:\:\:\:\:\:\: \\ $$$$ \\ $$ Answered by mehdee7396 last updated…
Question Number 218199 by Mamadi last updated on 01/Apr/25 $${describes}\:{the}\:{rupture}\:{body}\:{onQ} \\ $$$${of}\:{polynomials}. \\ $$$$\left.{a}\left.\right)\:{X}^{\mathrm{5}} +\mathrm{1}\:\:\:\:\:\:\:\:\:{b}\right)\:{X}^{\mathrm{6}} −{X}^{\mathrm{3}} +\mathrm{1} \\ $$ Answered by MrGaster last updated on…
Question Number 218195 by david2409 last updated on 01/Apr/25 $${P}=\frac{\Sigma{Fz}}{{Npil}} \\ $$ Answered by MrGaster last updated on 02/Apr/25 $$\left(\mathrm{1}\right):\Sigma{Fz}=\int_{\partial\Sigma} {FzdS} \\ $$$${Npil}=\int_{\partial\Sigma} {dS} \\…
Question Number 218188 by Mingma last updated on 01/Apr/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 218221 by Tawa11 last updated on 01/Apr/25 Commented by Tawa11 last updated on 01/Apr/25 $$ \\ $$Ground is rough But resistance not given…
Question Number 218189 by Mingma last updated on 01/Apr/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 218191 by Mamadi last updated on 01/Apr/25 $${exercises}\:{algebra}. \\ $$$${all}\:\:{algebraically}\:\:{closed}\:\:{fields} \\ $$$${ares}\:{finite}. \\ $$$${prouve}\:\:{it}\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 218187 by Mingma last updated on 01/Apr/25 Answered by efronzo1 last updated on 01/Apr/25 $$\mathrm{5}.\mathrm{1}\::\:\frac{\mathrm{k}}{\mathrm{5}}\:=\:\frac{\mathrm{2}}{\mathrm{3}}\:\Rightarrow\mathrm{k}=\frac{\mathrm{10}}{\mathrm{3}}\: \\ $$$$\:\mathrm{5}.\mathrm{2}\::\:\mathrm{6}+\mathrm{5k}=\mathrm{0}\:\Rightarrow\mathrm{k}=−\frac{\mathrm{6}}{\mathrm{5}} \\ $$ Terms of Service Privacy…