Question Number 203846 by York12 last updated on 30/Jan/24 $$\underset{{n}\rightarrow\infty} {\mathrm{lim}}\underset{{i}=\mathrm{2}} {\overset{{n}} {\prod}}\left(\frac{{i}^{\mathrm{2}} −\mathrm{1}}{{i}^{\mathrm{2}} }\right) \\ $$ Answered by MM42 last updated on 30/Jan/24 $${p}_{{n}}…
Question Number 203836 by patrice last updated on 29/Jan/24 Answered by Frix last updated on 30/Jan/24 $$\mathrm{In}\:\mathrm{3}\:\mathrm{steps}: \\ $$$$\mathrm{1}.\:{t}={x}^{\mathrm{2}} −\mathrm{1} \\ $$$$\mathrm{2}.\:{u}=\frac{\mathrm{5}{t}+\sqrt{\mathrm{25}{t}^{\mathrm{2}} +\mathrm{11}}}{\:\mathrm{11}} \\ $$$$\mathrm{3}.\:{v}=\frac{\sqrt{\mathrm{1}+{u}}}{\:\sqrt{\mathrm{1}−{u}}}\:\Rightarrow…
Question Number 203822 by 073 last updated on 29/Jan/24 Answered by esmaeil last updated on 29/Jan/24 $$\mathrm{1}:\frac{\mathrm{1}}{{x}}={p}\overset{{x}\rightarrow\infty\rightarrow{p}\rightarrow\mathrm{0}} {\rightarrow}\left[\frac{{x}+\mathrm{1}}{{x}}\right]=\left[{p}+\mathrm{1}\right)=\mathrm{1}\rightarrow \\ $$$$\Omega=\underset{{p}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{sinp}}{{p}}=\mathrm{1} \\ $$ Answered by…
Question Number 203832 by depressiveshrek last updated on 29/Jan/24 $$\mathrm{How}\:\mathrm{many}\:\mathrm{bit}\:\mathrm{strings}\:\mathrm{of}\:\mathrm{length}\:\mathrm{10}\:\mathrm{do}\:\mathrm{not} \\ $$$$\mathrm{have}\:\mathrm{four}\:\mathrm{consecutive}\:\mathrm{1s}? \\ $$ Answered by nikif99 last updated on 30/Jan/24 $${Total}\:{number}\:{of}\:{bit}\:{strings}\:{of}\:{length}\:\mathrm{10} \\ $$$${is}\:\mathrm{2}^{\mathrm{10}} =\mathrm{1024}\:\left(\mathrm{0}−\mathrm{1023}\right).…
Question Number 203833 by depressiveshrek last updated on 29/Jan/24 $$\mathrm{How}\:\mathrm{many}\:\mathrm{bit}\:\mathrm{strings}\:\mathrm{of}\:\mathrm{length}\:\mathrm{11}\:\mathrm{have} \\ $$$$\mathrm{exactly}\:\mathrm{three}\:\mathrm{consecutive}\:\mathrm{1s}? \\ $$ Answered by nikif99 last updated on 30/Jan/24 $${Such}\:{a}\:{typical}\:{bit}\:{string}\:{of}\:{length}=\mathrm{11}\:{is} \\ $$$$\mathrm{000}\underset{{pos}=\mathrm{4}} {\underbrace{\mathrm{111}}00000}…
Question Number 203835 by patrice last updated on 29/Jan/24 Answered by MathematicalUser2357 last updated on 30/Jan/24 $${bruh} \\ $$ Commented by Frix last updated on…
Question Number 203819 by zahaku last updated on 29/Jan/24 $$\frac{\mid{x}^{\mathrm{2}} −\mathrm{3}{x}\mid}{{x}^{\mathrm{2}} −\mathrm{9}}\:\:{draw}\:{up}\:{the}\:{variaton} \\ $$$${table}\:{of}\:{this}\:{function} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 203825 by necx122 last updated on 29/Jan/24 $${A}\:{sum}\:{of}\:\mathrm{2800}\:{is}\:{invested},\:{partly}\:{at}\:\mathrm{5\%} \\ $$$${and}\:{partly}\:{at}\:\mathrm{4\%}.\:{If}\:{the}\:{total}\:{income} \\ $$$${is}\:\mathrm{128}\:{per}\:{annum},\:{find}\:{the}\:{amount} \\ $$$${invested}\:{at}\:\mathrm{5\%}. \\ $$ Answered by esmaeil last updated on 29/Jan/24…
Question Number 203826 by necx122 last updated on 29/Jan/24 $${Evaluate} \\ $$$$\left(\mathrm{26}\:+\:\mathrm{15}\sqrt{\mathrm{3}}\right)^{\mathrm{1}/\mathrm{3}} +\:\left(\mathrm{26}\:−\:\mathrm{15}\sqrt{\mathrm{3}}\right)^{\mathrm{1}/\mathrm{3}} \\ $$ Answered by AST last updated on 29/Jan/24 $${Let}\:{a}=\sqrt[{\mathrm{3}}]{\mathrm{26}+\mathrm{15}\sqrt{\mathrm{3}}};{b}=\sqrt[{\mathrm{3}}]{\mathrm{26}−\mathrm{15}\sqrt{\mathrm{3}}}\Rightarrow{ab}=\mathrm{1} \\ $$$${a}^{\mathrm{3}}…
Question Number 203788 by BaliramKumar last updated on 28/Jan/24 $$\mathrm{The}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{all}\:\mathrm{possible}\:\mathrm{products}\:\mathrm{taken}\:\mathrm{two}\:\mathrm{at}\: \\ $$$$\mathrm{a}\:\mathrm{time}\:\:\mathrm{out}\:\mathrm{of}\:\mathrm{the}\:\mathrm{numbers}\:\pm\mathrm{1},\:\pm\mathrm{2},\:\pm\mathrm{3},\:\pm\mathrm{4}\:\mathrm{is} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{0}\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{b}\right)\:−\mathrm{30}\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{c}\right)\:\mathrm{30}\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{d}\right)\:\mathrm{55} \\ $$ Answered by mr W last updated on 28/Jan/24 $${to}\:{take}\:{two}\:{from}\:\mathrm{8}\:{there}\:{are}\:…