Question Number 203807 by aba last updated on 28/Jan/24 $$\mathrm{proof}\::\:\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{f}^{\mathrm{2}} \left(\mathrm{t}\right)\mathrm{dt}=\mathrm{0}\:\Rightarrow\:\mathrm{f}=\mathrm{0} \\ $$ Answered by JDamian last updated on 28/Jan/24 $$ \\ $$$$\mathrm{f}^{\mathrm{2}}…
Question Number 203800 by Bayat last updated on 28/Jan/24 Answered by esmaeil last updated on 28/Jan/24 $${just}\:{put}\:{zero}\:{instead}\:{of}\:{x} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 203803 by ajfour last updated on 28/Jan/24 Answered by ajfour last updated on 28/Jan/24 $$\mathrm{2}{s}^{\mathrm{2}} =\left({b}^{\mathrm{2}} +{c}^{\mathrm{2}} \right)−\left(\frac{{h}−{k}}{{h}+{k}}\right)\left({b}^{\mathrm{2}} −{c}^{\mathrm{2}} \right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:−\frac{\mathrm{2}{hk}}{\left({h}+{k}\right)^{\mathrm{2}} }\left({a}^{\mathrm{2}}…
Question Number 203809 by Fabricista15 last updated on 28/Jan/24 $${x}^{\mathrm{3}} +{y}^{\mathrm{3}} +{z}^{\mathrm{3}} =\mathrm{33} \\ $$ Answered by Fabricista15 last updated on 28/Jan/24 $$\mathrm{Ver}\:\mathrm{E}{quacao}\:{Diofantina} \\ $$…
Question Number 203794 by mr W last updated on 28/Jan/24 Commented by mr W last updated on 28/Jan/24 $${a}\:{triangual}\:{uniform}\:{thin}\:{rod}\:{frame}\: \\ $$$${with}\:{side}\:{lengthes}\:\boldsymbol{{a}},\:\boldsymbol{{b}},\:\boldsymbol{{c}}\:{and}\:{mass}\: \\ $$$$\boldsymbol{{M}}\:{is}\:{suspended}\:{through}\:{three}\:{thin} \\ $$$${strings}\:{with}\:{lengthes}\:\boldsymbol{{p}},\:\boldsymbol{{q}},\:\boldsymbol{{r}}\:{at}\:{its}…
Question Number 203772 by Calculusboy last updated on 27/Jan/24 Answered by witcher3 last updated on 27/Jan/24 $$\mathrm{no}\:\mathrm{close}\:\mathrm{formes}\:\mathrm{just}\:\mathrm{series}\:\mathrm{or}\:\mathrm{aproximination} \\ $$ Commented by Calculusboy last updated on…
Question Number 203774 by Calculusboy last updated on 27/Jan/24 $$\boldsymbol{{determine}}\:\boldsymbol{{whether}}\:\boldsymbol{{the}}\:\boldsymbol{{series}}\:\boldsymbol{{is}} \\ $$$$\boldsymbol{{convergent}}\:\boldsymbol{{or}}\:\boldsymbol{{divergent}} \\ $$$$\underset{\boldsymbol{{n}}=\mathrm{1}} {\overset{\infty} {\boldsymbol{\sum}}}\frac{\boldsymbol{{n}}}{\:\sqrt{\mathrm{4}\boldsymbol{{n}}^{\mathrm{2}} +\mathrm{1}}} \\ $$ Answered by witcher3 last updated on…
Question Number 203742 by Calculusboy last updated on 27/Jan/24 Answered by mr W last updated on 27/Jan/24 $${x}^{\mathrm{2024}} +{x}^{\mathrm{2024}} −\mathrm{2024}×\frac{\mathrm{1}}{\mathrm{4}}{x}^{\mathrm{2023}} +…=\mathrm{0} \\ $$$$\mathrm{2}{x}^{\mathrm{2024}} −\mathrm{506}{x}^{\mathrm{2023}} +…=\mathrm{0}…
Question Number 203771 by Calculusboy last updated on 27/Jan/24 Answered by DwaipayanShikari last updated on 27/Jan/24 $$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\begin{pmatrix}{{n}+\mathrm{3}}\\{\mathrm{3}}\end{pmatrix}} \\ $$$$=\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{{n}!}{\left({n}+\mathrm{3}\right)!\mathrm{3}!} \\ $$$$=\frac{\mathrm{1}}{\mathrm{3}!}\underset{{n}=\mathrm{0}}…
Question Number 203748 by patrice last updated on 27/Jan/24 Terms of Service Privacy Policy Contact: info@tinkutara.com