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Author: Tinku Tara

Question-203648

Question Number 203648 by yaslm last updated on 24/Jan/24 Answered by Frix last updated on 24/Jan/24 $${w}\left({x}+\frac{{l}}{\mathrm{2}}\right)\left({x}−\frac{{l}}{\mathrm{2}}\left(\mathrm{1}−\mathrm{i}\right)\right)\left({x}−\frac{{l}}{\mathrm{2}}\left(\mathrm{1}+\mathrm{i}\right)\right)=\mathrm{0} \\ $$$${x}=−\frac{{l}}{\mathrm{2}}\vee{x}=\frac{{l}}{\mathrm{2}}\left(\mathrm{1}\pm\mathrm{i}\right) \\ $$ Commented by yaslm last…

lim-x-1-2-x-tan-pix-2-

Question Number 203651 by Davidtim last updated on 24/Jan/24 $$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\left(\mathrm{2}−{x}\right)^{{tan}\left(\frac{\pi{x}}{\mathrm{2}}\right)} =? \\ $$ Answered by Mathspace last updated on 24/Jan/24 $${changement}\:\mathrm{1}−{x}={t}\:{give} \\ $$$${f}\left({x}\right)=\left(\mathrm{2}−{x}\right)^{{tan}\left(\frac{\pi{x}}{\mathrm{2}}\right)} \\…

Question-203625

Question Number 203625 by professorleiciano last updated on 23/Jan/24 Answered by esmaeil last updated on 23/Jan/24 $$\mathrm{1}+\frac{\left({sin}^{\mathrm{2}} {x}+{cos}^{\mathrm{2}} {x}\right)^{\mathrm{2}} −\mathrm{2}{sin}^{\mathrm{2}} {xcos}^{\mathrm{2}} {x}}{{sin}^{\mathrm{2}} {xcos}^{\mathrm{2}} {x}}=\mathrm{3}\rightarrow \\…