Question Number 203454 by Denis_volosenko352 last updated on 19/Jan/24 $$\sqrt{\mathrm{5}}+\sqrt{\mathrm{5}}={x} \\ $$$${x}×\mathrm{5}\pi=?\:{find}\:{all}\:{answers}\:{until}\:\mathrm{24}.\mathrm{01}.\mathrm{2024} \\ $$ Answered by MathematicalUser2357 last updated on 20/Jan/24 $${x}=\sqrt{\mathrm{5}}+\sqrt{\mathrm{5}}=\mathrm{2}\sqrt{\mathrm{5}} \\ $$$${x}×\mathrm{5}\pi=\mathrm{2}\sqrt{\mathrm{5}}×\mathrm{5}\pi=\mathrm{10}\pi\sqrt{\mathrm{5}} \\…
Question Number 203448 by hardmath last updated on 19/Jan/24 $$\mathrm{y}\:=\:\mathrm{sin3x}−\mathrm{ln}\left(\mathrm{3x}+\mathrm{1}\right)+\mathrm{3}^{\mathrm{2}\boldsymbol{\mathrm{x}}} \\ $$$$\mathrm{find}:\:\:\:\mathrm{y}^{'} \:=\:? \\ $$ Commented by hardmath last updated on 19/Jan/24 $$ \\ $$find…
Question Number 203445 by mathlove last updated on 19/Jan/24 Commented by mr W last updated on 19/Jan/24 $$\Rightarrow{Q}\mathrm{203387} \\ $$ Terms of Service Privacy Policy…
Question Number 203468 by MrGHK last updated on 19/Jan/24 $$\:\boldsymbol{\mathrm{let}}\:\boldsymbol{\mathrm{A}}\:{B}\:{and}\:{C}\:\:\boldsymbol{\mathrm{be}}\:\boldsymbol{\mathrm{sets}}\:\boldsymbol{\mathrm{prove}}\:\boldsymbol{\mathrm{using}}\:\boldsymbol{\mathrm{venn}}\:\boldsymbol{\mathrm{diagrams}}\:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{by}}\:\boldsymbol{\mathrm{first}}\:\boldsymbol{\mathrm{principle}} \\ $$$$\left.\:\boldsymbol{\mathrm{a}}\right)\boldsymbol{\mathrm{A}}×\left(\boldsymbol{\mathrm{B}}\cup\boldsymbol{\mathrm{C}}\right)=\left(\boldsymbol{\mathrm{A}}×\boldsymbol{\mathrm{B}}\right)\cup\left(\boldsymbol{\mathrm{A}}×\boldsymbol{\mathrm{C}}\right) \\ $$$$\left.\boldsymbol{\mathrm{b}}\right)\mathrm{A}×\left(\boldsymbol{\mathrm{B}}\cap\boldsymbol{\mathrm{C}}\right)=\left(\boldsymbol{\mathrm{A}}×\boldsymbol{\mathrm{B}}\right)\cap\left(\boldsymbol{\mathrm{A}}×\boldsymbol{\mathrm{C}}\right) \\ $$$$\left.\boldsymbol{\mathrm{c}}\right)\left(\boldsymbol{\mathrm{A}}−\boldsymbol{\mathrm{B}}\right)\cap\left(\boldsymbol{{A}}\cap\boldsymbol{\mathrm{B}}\right)\cap\left(\boldsymbol{\mathrm{B}}−\boldsymbol{\mathrm{A}}\right)=\left\{\right\} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 203471 by DEGWE last updated on 19/Jan/24 Answered by MathematicalUser2357 last updated on 20/Jan/24 $$=\frac{\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}{x}^{\mathrm{cosec}\:{x}+\mathrm{cot}\:{x}} }{\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\left(\mathrm{cosec}\:{x}+\mathrm{cot}\:{x}\right)} \\ $$$$=\frac{\underset{{x}\rightarrow\mathrm{0}^{+} }…
Question Number 203465 by princemurtuja last updated on 19/Jan/24 $$\mathrm{Focus}\:\mathrm{and}\:\mathrm{vertex}\:\mathrm{of}\:\mathrm{a}\:\mathrm{parabola}\:\mathrm{are}\:\mathrm{at}\:\left(\mathrm{3},\:\mathrm{4}\right)\:\mathrm{and}\:\left(\mathrm{0},\mathrm{0}\right). \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{directrix}. \\ $$ Answered by mr W last updated on 20/Jan/24 $${F}\left(\mathrm{3},\:\mathrm{4}\right) \\ $$$${V}\left(\mathrm{0},\:\mathrm{0}\right)…
Question Number 203434 by sonukgindia last updated on 19/Jan/24 Answered by witcher3 last updated on 20/Jan/24 $$=\int\frac{−\mathrm{2sin}\left(\mathrm{2x}\right)\mathrm{sin}\left(\mathrm{3x}\right)}{\mathrm{1}+\mathrm{2cos}\left(\mathrm{3x}\right)}\mathrm{dx} \\ $$$$=\frac{\mathrm{sin}\left(\mathrm{2x}\right)}{\mathrm{3}}\mathrm{ln}\left(\mathrm{1}+\mathrm{2cos}\left(\mathrm{3x}\right)\right)−\frac{\mathrm{1}}{\mathrm{6}}\int\mathrm{sin}\left(\mathrm{x}\right)\mathrm{cos}\left(\mathrm{x}\right)\mathrm{ln}\left(\mathrm{1}+\mathrm{2cos}\left(\mathrm{3x}\right)\right)\mathrm{dx} \\ $$$$\mathrm{ln}\left(\mathrm{1}+\mathrm{2cos}\left(\mathrm{3x}\right)\right)=\mathrm{ln}\left(\mathrm{1}+\mathrm{2cos}\left(\mathrm{x}\right)\left(\mathrm{2cos}^{\mathrm{2}} \left(\mathrm{x}\right)−\mathrm{1}\right)−\mathrm{4}\left(\mathrm{1}−\mathrm{cos}^{\mathrm{2}} \left(\mathrm{x}\right)\right)\mathrm{cos}\left(\mathrm{x}\right)\right) \\ $$$$=\mathrm{ln}\left(\mathrm{1}+\mathrm{8cos}^{\mathrm{3}}…
Question Number 203460 by MrGHK last updated on 19/Jan/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 203428 by cortano12 last updated on 19/Jan/24 $$\:\cancel{\underbrace{\:}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 203457 by DEGWE last updated on 19/Jan/24 Answered by witcher3 last updated on 19/Jan/24 $$\mathrm{tanh}\left(\mathrm{x}\right)=\frac{\mathrm{e}^{\mathrm{2x}} −\mathrm{1}}{\mathrm{e}^{\mathrm{2x}} +\mathrm{1}} \\ $$$$\mathrm{f}\left(\mathrm{x}\right)=\frac{\frac{\mathrm{1}+\mathrm{3}^{\mathrm{x}} +\mathrm{x}^{\mathrm{3}} +\mathrm{sh}\left(\mathrm{x}\right)}{\mathrm{1}−\mathrm{3}^{\mathrm{x}} −\mathrm{x}^{\mathrm{3}} −\mathrm{sh}\left(\mathrm{x}\right)}−\mathrm{1}}{\frac{\mathrm{1}+\mathrm{3}^{\mathrm{x}}…