Question Number 226983 by hardmath last updated on 24/Dec/25 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 226994 by Spillover last updated on 24/Dec/25 Answered by Spillover last updated on 25/Dec/25 Answered by Spillover last updated on 25/Dec/25 Answered by…
Question Number 226995 by Spillover last updated on 24/Dec/25 Answered by Ghisom_ last updated on 24/Dec/25 $$\underset{\mathrm{0}} {\overset{\pi/\mathrm{2}} {\int}}\frac{\mathrm{sin}^{\mathrm{3}} \:{x}\:\mathrm{cos}^{\mathrm{5}} \:{x}}{\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{sin}^{\mathrm{2}} \:{x}\right)^{\mathrm{3}} }{dx}=\underset{\mathrm{0}} {\overset{\pi/\mathrm{2}} {\int}}\frac{\left(\mathrm{1}+\mathrm{cos}\:\mathrm{2}{x}\right)\mathrm{sin}^{\mathrm{3}}…
Question Number 226973 by CrispyXYZ last updated on 23/Dec/25 $$\underset{{n}\rightarrow+\infty} {\mathrm{lim}}\left(\frac{\mathrm{sin}\:\frac{\mathrm{1}}{{n}}}{{n}+\frac{\mathrm{1}}{\mathrm{1}}}\:+\:\frac{\mathrm{sin}\:\frac{\mathrm{2}}{{n}}}{{n}+\frac{\mathrm{1}}{\mathrm{2}}}\:+\:…\:+\:\frac{\mathrm{sin}\:\frac{{n}}{{n}}}{{n}+\frac{\mathrm{1}}{{n}}}\right)=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 226961 by mnjuly1970 last updated on 22/Dec/25 $$\:\:\: \\ $$$$\:\:\:\:\:\sigma\:=\:\int_{\mathrm{0}} ^{\:\infty} {xe}^{−{x}} \:{J}_{\mathrm{2}} \left({x}\right){dx}=? \\ $$$$\:\:\:\: \\ $$ Answered by Tawa11 last updated…
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Question Number 226958 by efronzo1 last updated on 21/Dec/25 $$\:\:\:\mathrm{3}^{\mathrm{x}} =\mathrm{x}^{\mathrm{9}} \: \\ $$$$\:\:\:\:\mathrm{x}^{\mathrm{2}} =\:..? \\ $$ Answered by TonyCWX last updated on 21/Dec/25 $${x}\mathrm{ln}\left(\mathrm{3}\right)\:=\:\mathrm{9ln}\left({x}\right)…
Question Number 226942 by Spillover last updated on 20/Dec/25 Answered by Spillover last updated on 24/Dec/25 Answered by Spillover last updated on 24/Dec/25 Answered by…
Question Number 226943 by Spillover last updated on 20/Dec/25 Commented by fantastic2 last updated on 26/Dec/25 $${the}\:{rectangle}\:{is}\:{not}\:{unique} \\ $$ Commented by fantastic2 last updated on…
Question Number 226952 by Spillover last updated on 20/Dec/25 Answered by Spillover last updated on 24/Dec/25 $$\left({a}\right) \\ $$$${I}_{{n}} =\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {e}^{−{x}} \mathrm{cos}\:^{{n}} {xdx} \\…