Question Number 203103 by Mingma last updated on 10/Jan/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 203115 by Mathstar last updated on 10/Jan/24 Commented by Mathstar last updated on 10/Jan/24 $$\mathrm{Send}\:\mathrm{an}\:\mathrm{explanatory}\:\mathrm{solution},\:\mathrm{thank}\:\mathrm{you} \\ $$ Answered by mr W last updated…
Question Number 203127 by Skabetix last updated on 10/Jan/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 203111 by lazyboy last updated on 10/Jan/24 $${please}\:{solve}\:{it} \\ $$$$\int\left[{x}^{\frac{{x}}{\mathrm{2}}} +{e}^{{xlnx}} +\frac{\left(\Pi+\sqrt{{x}}{ln}\left({x}\right)\right)^{\mathrm{2}} }{\mathrm{2}{ln}\mathrm{2}\sqrt{{x}−{e}^{{x}} \mathrm{sin}\:{x}}}\right]^{\mathrm{2}} {dx}=? \\ $$ Commented by lazyboy last updated on…
Question Number 203104 by Mingma last updated on 10/Jan/24 Commented by Mingma last updated on 10/Jan/24 Continuation of the first post Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 203107 by cherokeesay last updated on 10/Jan/24 Commented by cherokeesay last updated on 10/Jan/24 Find the length x. Answered by AST last updated…
Question Number 203066 by mathlove last updated on 09/Jan/24 $${if}\:{p}=\frac{{x}^{\mathrm{2}} }{{x}−\mathrm{2}}−\frac{{x}}{\mathrm{1}+\frac{\mathrm{2}}{{x}}}−\frac{\mathrm{4}}{\mathrm{1}+\frac{\mathrm{4}}{{x}^{\mathrm{2}} }}\:\:\:{and}\:{x}−\frac{\mathrm{4}}{{x}}=\mathrm{2} \\ $$$${then}\:{show}\:{that}\:\:\left(\frac{\mathrm{32}}{{p}}\right)^{\mathrm{2}} =\mathrm{80} \\ $$ Answered by Rasheed.Sindhi last updated on 09/Jan/24 $${if}\:{p}=\frac{{x}^{\mathrm{2}}…
Question Number 203062 by ajfour last updated on 09/Jan/24 Answered by ajfour last updated on 09/Jan/24 $$\mathrm{tan}\:\theta=\frac{{R}−\left(\mathrm{1}−{R}\right)}{{x}−{c}}=\frac{\mathrm{1}}{{x}} \\ $$$$\&\:\:{x}^{\mathrm{2}} ={R}^{\mathrm{2}} −\left(\mathrm{1}−{R}\right)^{\mathrm{2}} =\mathrm{2}{R}−\mathrm{1} \\ $$$$\Rightarrow\:\frac{{x}−{c}}{{x}}=\frac{\mathrm{2}{R}−\mathrm{1}}{\mathrm{1}}={x}^{\mathrm{2}} \\…
Question Number 203063 by LowLevelLump last updated on 09/Jan/24 Answered by MM42 last updated on 09/Jan/24 $${f}'={e}^{{x}} −{a}=\mathrm{0}\Rightarrow\alpha={lna} \\ $$$$\Rightarrow{minf}={a}−{alna} \\ $$$$\:{g}'={a}−\frac{\mathrm{1}}{{x}}=\mathrm{0}\Rightarrow\beta=\frac{\mathrm{1}}{{a}} \\ $$$$\Rightarrow{ming}=\mathrm{1}+{lna} \\…
Question Number 203090 by hardmath last updated on 09/Jan/24 Terms of Service Privacy Policy Contact: info@tinkutara.com