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x-1-x-625-solve-for-x-

Question Number 202813 by pascal889 last updated on 03/Jan/24 $$\left(\boldsymbol{\mathrm{x}}\:+\:\mathrm{1}\right)^{\boldsymbol{\mathrm{x}}} \:\:=\:\mathrm{625} \\ $$$$\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\:\boldsymbol{\mathrm{x}} \\ $$$$ \\ $$ Commented by mr W last updated on 03/Jan/24…

1-S-n-a-a-d-a-d-a-2d-a-n-1-d-a-n-d-2-S-n-a-a-d-a-2d-a-d-a-2d-a-3d-a-n-1-d-a-n-d-a-n-1-d-

Question Number 202774 by BaliramKumar last updated on 03/Jan/24 $$\mathrm{1}.\:\:\:\:\:\:\mathrm{S}_{\mathrm{n}} \:=\:\mathrm{a}\left(\mathrm{a}+\mathrm{d}\right)+\left(\mathrm{a}+\mathrm{d}\right)\left(\mathrm{a}+\mathrm{2d}\right)+……+\left\{\mathrm{a}+\left(\mathrm{n}−\mathrm{1}\right)\mathrm{d}\right\}\left\{\mathrm{a}+\left(\mathrm{n}\right)\mathrm{d}\right\} \\ $$$$\mathrm{2}.\:\:\:\:\:\:\mathrm{S}_{\mathrm{n}} \:=\:\mathrm{a}\left(\mathrm{a}+\mathrm{d}\right)\left(\mathrm{a}+\mathrm{2d}\right)+\left(\mathrm{a}+\mathrm{d}\right)\left(\mathrm{a}+\mathrm{2d}\right)\left(\mathrm{a}+\mathrm{3d}\right)+……+\left\{\mathrm{a}+\left(\mathrm{n}−\mathrm{1}\right)\mathrm{d}\right\}\left\{\mathrm{a}+\left(\mathrm{n}\right)\mathrm{d}\right\}\left\{\mathrm{a}+\left(\mathrm{n}+\mathrm{1}\right)\mathrm{d}\right\} \\ $$$$ \\ $$ Answered by Rasheed.Sindhi last updated on 03/Jan/24…

determine-whether-this-signal-is-periodic-or-not-if-it-s-periodic-specify-it-s-faundemwntal-period-y-n-cos-n-8-cos-npi-8-

Question Number 202771 by ali009 last updated on 03/Jan/24 $${determine}\:{whether}\:{this}\:{signal}\:{is}\:{periodic} \\ $$$${or}\:{not}\:{if}\:{it}'{s}\:{periodic}\:{specify}\:{it}'{s}\: \\ $$$${faundemwntal}\:{period} \\ $$$${y}\left({n}\right)={cos}\left(\frac{{n}}{\mathrm{8}}\right){cos}\left(\frac{{n}\pi}{\mathrm{8}}\right)\: \\ $$ Answered by Frix last updated on 03/Jan/24…

2-8-2-1-4-2-2-4-1-1-6-3-1-6-3-4-2-5-5-2-6-5-2-

Question Number 202796 by MathematicalUser2357 last updated on 03/Jan/24 $$\left[\mathrm{2}^{\mathrm{8}\boldsymbol{\div}\mathrm{2}−\mathrm{1}} +\mathrm{4}\boldsymbol{\div}\left\{\mathrm{2}+\mathrm{2}^{\mathrm{4}\boldsymbol{\div}\left(\mathrm{1}+\mathrm{1}\right)} \boldsymbol{\div}\left(\mathrm{6}\boldsymbol{\div}\mathrm{3}−\mathrm{1}\right)\right\}\right]\boldsymbol{\div}\left[\mathrm{6}\boldsymbol{\div}\left\{\left(\mathrm{3}^{\mathrm{4}\boldsymbol{\div}\mathrm{2}} +\mathrm{5}\boldsymbol{\div}\mathrm{5}\right)\boldsymbol{\div}\mathrm{2}−\mathrm{6}\boldsymbol{\div}\left(\mathrm{5}−\mathrm{2}\right)\right\}\right] \\ $$ Answered by a.lgnaoui last updated on 03/Jan/24 $$\mathrm{si}\:\left(\:\frac{.}{.}\right)\:\:\mathrm{est}\:\mathrm{une}\:\mathrm{operation}\:\mathrm{de}\left[\mathrm{division}\right. \\ $$$$\:\:\Rightarrow\:\mathrm{Expression}\:\mathrm{est}\:\mathrm{equivalente}\:\mathrm{a}…

if-f-1-f-0-f-2-0-and-f-1-6-then-find-f-x-

Question Number 202795 by mathlove last updated on 03/Jan/24 $${if}\:{f}\left(−\mathrm{1}\right)={f}\left(\mathrm{0}\right)={f}\left(\mathrm{2}\right)=\mathrm{0}\:{and}\:{f}\left(\mathrm{1}\right)=\mathrm{6} \\ $$$${then}\:{find}\:{f}\left({x}\right)=? \\ $$ Answered by AST last updated on 03/Jan/24 $${If}\:{f}\left({x}\right)\:{is}\:{a}\:{polynomial}:\:{x}\left({x}+\mathrm{1}\right)\left({x}−\mathrm{2}\right)\left({x}−\mathrm{4}\right) \\ $$ Answered…

Une-dette-de-100-000-Euros-a-ete-acorde-a-une-personne-pour-une-duree-de-3-mois-sans-interet-suiuvant-condions-suivantes-un-capital-de-500-000-euros-au-moins-dans-le-compte-du-debiteur-un-spec

Question Number 202820 by a.lgnaoui last updated on 04/Jan/24 $$\boldsymbol{\mathrm{U}}\mathrm{ne}\:\mathrm{dette}\:\:\mathrm{de}\:\mathrm{100}\:\mathrm{000}\:\mathrm{Euros}\:\mathrm{a}\:\mathrm{ete}\:\mathrm{acorde}\:\mathrm{a}\:\mathrm{une}\:\mathrm{personne}\: \\ $$$$\mathrm{pour}\:\mathrm{une}\:\mathrm{duree}\:\boldsymbol{\mathrm{de}}\:\mathrm{3}\:\boldsymbol{\mathrm{mois}}\:\mathrm{sans}\:\mathrm{interet}\:\mathrm{suiuvant}\: \\ $$$$\mathrm{condions}\:\mathrm{suivantes} \\ $$$$\bullet\mathrm{un}\:\mathrm{capital}\:\mathrm{de}\:\mathrm{500}\:\mathrm{000}\:\mathrm{euros}\:\mathrm{au}\:\mathrm{moins}\: \\ $$$$\:\mathrm{dans}\:\mathrm{le}\:\mathrm{compte}\:\mathrm{du}\:\mathrm{debiteur}. \\ $$$$\bullet\mathrm{un}\:\mathrm{specimen}\:\mathrm{de}\:\mathrm{cheque}\:\mathrm{barre}\: \\ $$$$\bullet\mathrm{un}\:\mathrm{interet}\:\mathrm{de}\:\mathrm{5\%}\:\mathrm{aplique}\:\:\mathrm{a}\:\mathrm{partir}\:\mathrm{du}\: \\ $$$$\boldsymbol{\mathrm{deuxieme}}\:\boldsymbol{\mathrm{mois}}\:\:\mathrm{et}\:\mathrm{pendant}\:\mathrm{1}\:\mathrm{mois}\: \\…