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Author: Tinku Tara

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Question Number 204691 by Davidtim last updated on 25/Feb/24 $$\sqrt{{a}\boldsymbol{\div}\sqrt{{a}\boldsymbol{\div}\sqrt{{a}\boldsymbol{\div}\centerdot\centerdot\centerdot\boldsymbol{\div}\sqrt{{a}}}}}=? \\ $$ Answered by Faetmaaa last updated on 27/Feb/24 $$\forall{a}\in\boldsymbol{\mathrm{R}}\backslash\left\{\mathrm{0}\right\} \\ $$$${x}\::=\:\sqrt{\frac{{a}}{\:\sqrt{\frac{{a}}{\:\sqrt{\frac{{a}}{\ldots}}}}}} \\ $$$$\Rightarrow{x}=\sqrt{\frac{{a}}{{x}}} \\…

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Question Number 204686 by Davidtim last updated on 25/Feb/24 $$\sqrt{{a}−\sqrt{{a}−\sqrt{{a}−\centerdot\centerdot\centerdot}}}=? \\ $$ Commented by A5T last updated on 25/Feb/24 $${If}\:\sqrt{{a}−\sqrt{{a}−\sqrt{{a}−…}}}\:{converges},\:{then}\:\sqrt{{a}−{x}}={x} \\ $$$$\Rightarrow{x}^{\mathrm{2}} +{x}−{a}=\mathrm{0}\Rightarrow{x}=\frac{−\mathrm{1}\underset{−} {+}\sqrt{\mathrm{1}+\mathrm{4}{a}}}{\mathrm{2}} \\…