Question Number 202650 by liuxinnan last updated on 31/Dec/23 Answered by liuxinnan last updated on 01/Jan/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 202651 by hardmath last updated on 31/Dec/23 Commented by Frix last updated on 31/Dec/23 $${y}=\frac{\mathrm{3cos}\:{x}\:+\mathrm{sin}\:{x}}{\mathrm{10}}+{c}_{\mathrm{1}} \mathrm{e}^{\mathrm{2}{x}} +{c}_{\mathrm{2}} \mathrm{e}^{{x}} \\ $$ Answered by Mathspace…
Question Number 202677 by BaliramKumar last updated on 31/Dec/23 $$ \\ $$$$\mathrm{If}\:{x}^{\mathrm{2}} \:−\:{y}^{\mathrm{2}} \:=\:\mathrm{2023}^{\mathrm{2024}} \:\&\:{x},\:{y}\:\in\:\boldsymbol{\mathrm{N}} \\ $$$$\mathrm{how}\:\mathrm{many}\:\mathrm{set}\left\{{x},\:{y}\right\} \\ $$ Answered by AST last updated on…
Question Number 202679 by Mingma last updated on 31/Dec/23 Answered by esmaeil last updated on 31/Dec/23 $$\curvearrowright\rightarrow<_{{hex}} =\mathrm{120}\rightarrow \\ $$$${tan}\mathrm{30}=\frac{{h}}{\frac{{a}}{\mathrm{2}}}\rightarrow{h}=\frac{\sqrt{\mathrm{3}}{a}}{\mathrm{6}} \\ $$$$\mathrm{2}\left(\frac{{a}}{\mathrm{2}}×\frac{\sqrt{\mathrm{3}}{a}}{\mathrm{6}}×\frac{\mathrm{1}}{\mathrm{2}}\right)=\mathrm{43}=\left({S}_{{blue}} +{S}_{{pink}} \right)\rightarrow \\…
Question Number 202672 by BaliramKumar last updated on 31/Dec/23 $$\mathrm{The}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{all}\:\mathrm{the}\:\mathrm{divisors}\:\mathrm{of}\:\mathrm{24}\:\mathrm{is}\:\mathrm{60}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{all}\:\mathrm{the}\:\mathrm{divisors}\:\mathrm{of}\:\mathrm{24}×\mathrm{79}. \\ $$ Answered by a.lgnaoui last updated on 31/Dec/23 $$\mathrm{60} \\ $$ Commented…
Question Number 202701 by cherokeesay last updated on 31/Dec/23 Commented by nikif99 last updated on 01/Jan/24 $${Be}\:{prepared}\:{for}\:{the}\:{next}\:{year},\:{too}. \\ $$$${Happy}\:{and}\:{prosperous}\:{new}\:{year}. \\ $$ Terms of Service Privacy…
Question Number 202638 by depressiveshrek last updated on 31/Dec/23 $$\sqrt{{x}−\frac{\mathrm{1}}{{x}}}−\sqrt{\mathrm{1}−\frac{\mathrm{1}}{{x}}}=\mathrm{1}−\frac{\mathrm{1}}{{x}} \\ $$ Commented by AST last updated on 31/Dec/23 $${x}=\mathrm{1}.{Suppose}\:{x}\neq\mathrm{1},{let}\:{a}=\sqrt{{x}−\frac{\mathrm{1}}{{x}}};{b}=\sqrt{\mathrm{1}−\frac{\mathrm{1}}{{x}}} \\ $$$${a}−{b}=\mathrm{1}−\frac{\mathrm{1}}{{x}};\left({a}+{b}\right)^{\mathrm{2}} =\mathrm{1}+{x} \\ $$$${a}^{\mathrm{2}}…
Question Number 202698 by Bambamamoudou last updated on 31/Dec/23 $${determine}\:{le}\:{reste}\:{de}\:{la}\:{division}\:{eucludienne}\:{de}\:\mathrm{2023}^{\mathrm{2019}} {par}\:\mathrm{13} \\ $$ Answered by Rasheed.Sindhi last updated on 01/Jan/24 $$\because\:{gcd}\left(\mathrm{2023},\mathrm{13}\right)=\mathrm{1} \\ $$$$\therefore\:\:\:\:\mathrm{2023}^{\phi\left(\mathrm{13}\right)} \equiv\mathrm{1}\left({mod}\:\mathrm{13}\right) \\…
Question Number 202694 by Mingma last updated on 31/Dec/23 Answered by a.lgnaoui last updated on 01/Jan/24 $$\Delta\boldsymbol{\mathrm{KTP}} \\ $$$$ \\ $$ Commented by a.lgnaoui last…
Question Number 202589 by mnjuly1970 last updated on 30/Dec/23 $$ \\ $$$$\:\:\Omega\:=\:\underset{{k}=\mathrm{1}} {\overset{\infty} {\sum}}\left(\frac{\mathrm{1}}{{k}}\:+\:\mathrm{2}{ln}\left(\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}{k}}\right)\right)=?\:\:\:\:\: \\ $$$$ \\ $$$$ \\ $$ Commented by mnjuly1970 last updated…