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Question Number 204405 by mathdave last updated on 16/Feb/24 Commented by mathdave last updated on 16/Feb/24 $${pls}\:{someone}\:{should}\:{me}\:{out}\: \\ $$ Answered by mr W last updated…
Question Number 204417 by Frix last updated on 16/Feb/24 $$\mathrm{Solve}\:\mathrm{for}\:{z}\in\mathbb{C} \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{e}^{{z}} =\mathrm{ln}\:{z} \\ $$ Answered by mr W last updated on 17/Feb/24…
Question Number 204396 by Thierrybadouana last updated on 15/Feb/24 Answered by Faetmaaa last updated on 27/Feb/24 $$\mathrm{ln}\left(\mathrm{1}+{y}\right)\:\underset{{y}\rightarrow\mathrm{0}} {\sim}\:{y} \\ $$$$\mathrm{sin}\left({y}\right)\:\underset{{y}\rightarrow\mathrm{0}} {\sim}\:{y} \\ $$$$\underset{\begin{matrix}{{x}\rightarrow\mathrm{0}}\\{{x}\neq\mathrm{0}}\end{matrix}} {\mathrm{lim}}\:\frac{\mathrm{ln}\left(\mathrm{1}+{x}^{\mathrm{2}} \right)}{\mathrm{sin}^{\mathrm{2}}…
Question Number 204393 by ks last updated on 15/Feb/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 204394 by ks last updated on 15/Feb/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 204395 by Thierrybadouana last updated on 15/Feb/24 Answered by Lindemann last updated on 20/Feb/24 $$=\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{{ln}\left(\mathrm{1}+{x}^{\mathrm{2}} \right)}{{x}^{\mathrm{2}} }×\frac{{x}^{\mathrm{2}} }{{sin}^{\mathrm{2}} \left({x}\right)}\right)\:=\:\mathrm{1} \\ $$ Terms…
Question Number 204389 by Ngarmadji last updated on 15/Feb/24 Answered by Frix last updated on 15/Feb/24 $$\frac{\mathrm{2}{x}}{\mathrm{3}}−\frac{\mathrm{2}{x}}{\mathrm{5}}=\mathrm{1}\:\:\frac{{x}}{\mathrm{3}}−\frac{{x}}{\mathrm{5}}=\frac{\mathrm{1}}{\mathrm{2}}\:\:\mathrm{5}{x}−\mathrm{3}{x}=\frac{\mathrm{15}}{\mathrm{2}}\:\:{x}=\frac{\mathrm{15}}{\mathrm{4}} \\ $$$$\frac{\mathrm{3}{x}}{\mathrm{5}}−\frac{\mathrm{2}{x}}{\mathrm{15}}+\frac{{x}}{\mathrm{3}}=−\frac{\mathrm{7}}{\mathrm{15}}\:\:\frac{\mathrm{9}{x}−\mathrm{2}{x}+\mathrm{5}{x}}{\mathrm{15}}=−\frac{\mathrm{7}}{\mathrm{15}}\:\:…\:{x}=−\frac{\mathrm{7}}{\mathrm{12}} \\ $$ Terms of Service Privacy…
Question Number 204384 by Abdullahrussell last updated on 15/Feb/24 Commented by Frix last updated on 15/Feb/24 $$\mathrm{35}^{\mathrm{36}} =\mathrm{10}{m}+\mathrm{5} \\ $$$$\mathrm{36}^{\mathrm{35}} =\mathrm{10}{n}+\mathrm{6} \\ $$$$\mathrm{4}^{\mathrm{10}{m}+\mathrm{5}} =\mathrm{100}{k}+\mathrm{24} \\…
Question Number 204348 by BaliramKumar last updated on 14/Feb/24 $$\mathrm{3}×\mathrm{7}×\mathrm{11}\:+\:\mathrm{7}×\mathrm{11}×\mathrm{15}\:+\:\mathrm{11}×\mathrm{15}×\mathrm{19}\:+\:……….+\:\:\mathrm{39}×\mathrm{43}×\mathrm{47}\:=\:?\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\ $$ Answered by MM42 last updated on 14/Feb/24 $$\underset{\mathrm{1}} {\overset{\mathrm{10}} {\sum}}\:\left(\mathrm{4}{n}−\mathrm{1}\right)\left(\mathrm{4}{n}+\mathrm{3}\right)\left(\mathrm{4}{n}+\mathrm{7}\right) \\ $$$$=\underset{\mathrm{1}} {\overset{\mathrm{10}}…